Note that 1 calorie (4.2 J) is the energy needed to raise 1 gram of water...

Note that 1 calorie (4.2 J) is the energy needed to raise 1 gram of water 1 degree, and recall that a food calorie is actually a kilocalorie
Use whatever approximations you need, but state what they are.

Show your work.

1) How much ice water must you drink and so heat up to equal the energy in a chocolate glazed donut?

2) Will drinking ice water work as a weight loss strategy?

3) How about standing on a windy mountaintop soaking wet?

4) How far must you job to burn off the calories in that donut?

Expert Solution

Amanda K answered 3 years ago

he food calorie, equal to 4186 J, is a measure of how much energy is released...

he food calorie, equal to 4186 J, is a measure of how much energy is released when food is metabolized by the body. A certain brand of fruit-and-cereal bar contains 130 food calories per bar. Part A If a 72.0 kg hiker eats one of these bars, how high a mountain must he climb to "work off" the calories, assuming that all the food energy goes only into increasing gravitational potential energy? Express your answer in meters. h h =...

1.) A surface described by the area vector A = + 4.2 i - 4.3 j...

1.) A surface described by the area vector A = + 4.2 i - 4.3 j - 1.8 k is located in a uniform electric field given by E = - 2.0 i - 2.5 j + 4.0 k. Calculate the electric flux through this surface. 2.)An isolated spherical conductor has an excess charge of -13.6 μC placed on its surface. Inside the conductor is a cavity, within which is a point charge of 5.70 μC. How many excess electrons...

What is the energy (kcal) that must be removed to take 36.7 gram of water from...

What is the energy (kcal) that must be removed to take 36.7 gram of water from 100°C steam to 35°C liquid water?

How much energy is required to raise the temperature of 100g of water from -10 to...

How much energy is required to raise the temperature of 100g of water from -10 to 110°C?

Spring Water Company Ltd. needed to raise $50 million of additional capital to finance the expansion...

Spring Water Company Ltd. needed to raise $50 million of additional capital to finance the expansion of its bottled water facility. After consulting an investment banker, it decided to issue bonds. The bonds had a face value of $50 million and an annual interest rate of 4.5%, paid semi-annually on June 30 and December 31, and will reach maturity on December 31, 2026. The bonds were issued at 96.1 on January 1, 2016, for $48,050,000, which represented a yield of...

Calculate the amount of energy in kilojoules needed to change 315 g of water ice at...

Calculate the amount of energy in kilojoules needed to change 315 g of water ice at –10 ∘C to steam at 125 ∘C. The following constants may be useful: Cm (ice)=36.57 J mol−1 ∘C−1 Cm (water)=75.40 J mol−1 ∘C−1 Cm (steam)=36.04 J mol−1 ∘C−1 ΔfusH=+6.01 kJ mol−1 ΔvapH=+40.67 kJ mol−1

Based on the thermodynamic properties provided for water, determine the amount of energy needed for 269...

Based on the thermodynamic properties provided for water, determine the amount of energy needed for 269 g of water to go from 85.5 °C to 161 °C. Property Value Units Melting point 0.0 °C Boiling point 100.0 °C ΔHfusΔHfus 6.01 kJ/mol ΔHvapΔHvap 40.67 kJ/mol cp (s) 37.1 J/mol·°C cp (l) 75.3 J/mol·°C cp (g) 33.6 J/mol·°C

Calculate the amount of energy in kilojoules needed to change 333 g of water ice at...

Calculate the amount of energy in kilojoules needed to change 333 g of water ice at −10 ∘C to steam at 125 ∘C. The following constants may be useful: Cm (ice)=36.57 J/(mol⋅∘C) Cm (water)=75.40 J/(mol⋅∘C) Cm (steam)=36.04 J/(mol⋅∘C) ΔHfus=+6.01 kJ/mol ΔHvap=+40.67 kJ/mol

Calculate the amount of energy in kilojoules needed to change 153 g of water ice at...

Calculate the amount of energy in kilojoules needed to change 153 g of water ice at –10 ∘C to steam at 125 ∘C. The following constants may be useful: Cm (ice)=36.57 J mol−1 ∘C−1 Cm (water)=75.40 J mol−1 ∘C−1 Cm (steam)=36.04 J mol−1 ∘C−1 ΔfusH=+6.01 kJ mol−1 ΔvapH=+40.67 kJ mol−1

Calculate the amount of energy in kilojoules needed to change 279g of water ice at ?10...

Calculate the amount of energy in kilojoules needed to change 279g of water ice at ?10 ?C to steam at 125 ?C. The following constants may be useful: Cm (ice)=36.57 J/(mol??C) Cm (water)=75.40 J/(mol??C) Cm (steam)=36.04 J/(mol??C) ?Hfus=+6.01 kJ/mol ?Hvap=+40.67 kJ/mol

Question