Question

1. Suppose you own a fish restaurant and you believe that the demand for sea bass is distributed normally (that is, follows the bell-shaped curve) with a mean of 12 pounds and a standard deviation of 3.2. In summary, we express this as N(12,3.2).

   1a. The notation N(12,3.2) means that

   		The mean (average) is 3.2 and the standard deviation is 12
   		The mean is 12 and the standard deviation is 3.2 and the data follows a bell shape curve
   		The mean is 12 and the standard deviation is 3.2 and the data does not follow a bell shape curve

10 points

Question 2

1. What is the z-score for 20 pounds of sea bass? You find the z-score by calculating (x-mean)/standard deviation

   		0.0062
   		2.50
   		0.9938
   		0.25

10 points

Question 3

1. The number inside Table A associated with 2.50 is

   		2.50
   		0.0062
   		0.9938
   		0.25

10 points

Question 4

1. The number in the table represents that area to the

   		Right
   		Left

10 points

Question 5

1. So 0.9938 is the area associated with a Z score of

   		2.50 or more
   		2.50 or less

10 points

Question 6

1. The probability that you will need 20 pounds or more of sea bass is

   		0.25
   		0.0062
   		0.9938
   		2.50

10 points

Question 7

1. What is the z-score for 15 pounds of sea bass

   		0.94
   		0.8264
   		0.06
   		-0.94

10 points

Question 8

1. What is the number inside table A associated with 0.94

   		0.8264
   		0.1736
   		0.94

10 points

Question 9

1. So 0.8264 is the area associated with a Z score of

   		0.94 or less
   		0.94 or more

10 points

Question 10

1. The probability that you will need 15 pounds of sea bass or less is

   		0.1736
   		0.94
   		0.8264

10 points

Question 11

1. What is the probability that you will need between 15 and 20 pounds of sea bass

   		0.94
   		0.8264
   		0.1674

10 points

Question 12

1. What is the z-score associated with the 95th percentile of the standard normal curve

   		0.95
   		1.65
   		1.28

10 points

Question 13

1. How many pounds of sea bass are needed for the 95th percentile of sea bass demand

   		1.65
   		7.28
   		17.28

Answer 1

Question 1

The notation N(12,3.2) means that

The mean is 12 and the standard deviation is 3.2 and the data follows a bell shape curve

Question 2

1. What is the z-score for 20 pounds of sea bass? You find the z-score by calculating (x-mean)/standard deviation

2.50

Question 3

1. The number inside Table A associated with 2.50 is

0.9938

Question 4

1. The number in the table represents that area to the

left

Question 5

1. So 0.9938 is the area associated with a Z score of

2.50 or less

Question 6

1. The probability that you will need 20 pounds or more of sea bass is

0.0062

Question 7

1. What is the z-score for 15 pounds of sea bass

0.94

Question 8

1. What is the number inside table A associated with 0.94

0.8264

Question 9

So 0.8264 is the area associated with a Z score of

0.94 or less

Question 10

1. The probability that you will need 15 pounds of sea bass or less is

0.8264

Question 11

1. What is the probability that you will need between 15 and 20 pounds of sea bass

0.1674

Question 12

1. What is the z-score associated with the 95th percentile of the standard normal curve

1.65

Question 13

1. How many pounds of sea bass are needed for the 95th percentile of sea bass demand

17.28