In: Statistics and Probability
The Wisconsin Fish and Game Department stocked a lake
with 30% catfish, 15 % bass, 40% bluegill, and 15% Northern Pike.
Five years later they took a random sample of 500 fish from the
lake and found 120 catfish, 85 bass, 220 bluegill, and 75 Northern
Pike. At the 5% level of significance, can we show that the
distribution of fish changed over the 5-year interval? State and
test appropriate hypotheses. State conclusions.
the necessary calculation table :-
types | observed | test proportion | expected | |
catfish | 120 | 0.30 | 500*0.30 = 150 | (120-150)^2/150 = 6 |
bass | 85 | 0.15 | 500*0.15 = 75 | 1.33333 |
bluegill | 220 | 0.40 | 500*0.40 = 200 | 2 |
pike | 75 | 0.15 | 500*0.15 = 75 | 0 |
sum= 500 | sum= 9.33333 |
hypothesis:-
at least one of the proportions are different.
test statistic is :-
degrees of freedom = (4-1) = 3
p value is = 0.0252
[ in any blank cell of excel type =CHISQ.DIST.RT(9.3333,3)]
decision:-
p value = 0.0252 < 0.05 (alpha)
we reject the null hypothesis and conclude that there is enough evidence to claim that the distribution of fish changed over the 5-year interval at 0.05 level of significance.
*** if you have any doubt regarding the problem please write it in the comment box.if you are satisfied please give me a LIKE if possible...