Question

In: Statistics and Probability

Find the regression equation using the following set of data with y as the response variable....

Find the regression equation using the following set of data with y as the response variable.

x y
40.2 82.2
54.2 111.8
43 84.3
30.7 68.5
33 90.8
42.8 78.5
30.9 71.7
28.6 69.8
36.6 83.1
41.1 93.9
26.6 63.9
45.5 95.5

What is the correlation coefficient? use three decimal places.
r =  

What is the regression line equation. Use each value to three decimal places.

ˆyy^ =  +  x

What is the predicted value of the response variable, when using a value of 32.1 as the explanatory variable. ? Write answer accurate to one decimal place.
ˆyy^ =  

Solutions

Expert Solution

X Y X * Y X2 Y2
40.2 82.2 3304.44 1616.04 6756.84
54.2 111.8 6059.56 2937.64 12499.24
43 84.3 3624.9 1849 7106.49
30.7 68.5 2102.95 942.49 4692.25
33 90.8 2996.4 1089 8244.64
42.8 78.5 3359.8 1831.84 6162.25
30.9 71.7 2215.53 954.81 5140.89
28.6 69.8 1996.28 817.96 4872.04
36.6 83.1 3041.46 1339.56 6905.61
41.1 93.9 3859.29 1689.21 8817.21
26.6 63.9 1699.74 707.56 4083.21
45.5 95.5 4345.25 2070.25 9120.25
Total 453.2 994 38605.6 17845.36 84400.92

Part a)



r = 0.868

Equation of regression line is Ŷ = a + bX


b = 1.461
a =( Σ Y - ( b * Σ X) ) / n
a =( 994 - ( 1.4606 * 453.2 ) ) / 12
a = 27.671
Equation of regression line becomes Ŷ = 27.671 + 1.461 X

When X = 32.1
Ŷ = 27.671 + 1.461 X
Ŷ = 27.671 + ( 1.461 * 32.1 )
Ŷ = 74.6


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