in an experiment, 15.0 g of ice at -30 celsius is converted into steam with a...

in an experiment, 15.0 g of ice at -30 celsius is converted into steam with a temperature of 115 celsius. How much energy is required for this process? DHvap= 2260 J/g; DHfus= 334 J/g; cs(ice)= 2.06 J/(g celsius; cs(water)= 4.18 J/(g celsius; cs(steam)= 1.99 J/(g celsius))

Expert Solution

ice converted to 0⁰C water q1 = mcT

= 15*2.06*(0-(-30)

= 15*2.06*30 = 927J

heat of fustion of ice q2 = m*H fus

= 15*334 = 5010J

water converted to vapor q3 = mcT

= 15*4.18*(100-0) = 6270J

water vapor converted to 115⁰C q4 = mcT

= 15*1.99*(115-100)

= 447.75J

heat of vaporisation q5 = m*Hvap

= 15*2260 = 33900J

The total energy q = q1+ q2+q3+q4+q5

= 927+5010+6270+447.75+ 33900 = 46554.75J

queen_honey_blossom answered 2 years ago

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