Suppose you take a 35.00 mL sample of this acid solution. You then titrate it with...

Suppose you take a 35.00 mL sample of this acid solution. You then titrate it with a 0.1522 M sodium hydroxide solution. A volume of 39.25 mL of the sodium hydroxide was required to complete the titration. What is the concentration of this unknown hydrochloric acid solution? (shortest and easiest way please)

Expert Solution

HCl(aq) + NaOH(aq) ---------------> NaCl(aq) + H2O(l)

1 mole 1 mole

HCl NaOH

M1 = M2 = 0.1522M

V1 = 35ml V2 = 39.25ml

n1 = 1 n2 = 1

M1V1/n1 = M2V2/n2

M1 = M2V2n1/V1n2

= 0.1522*39.25*1/35*1

= 0.171M

The concentration of unknown hydrochloric acid is 0.171M

queen_honey_blossom answered 2 years ago

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