In: Math
Please walk me through SPSS setup for this and complete the following:
Consider the data below of inches of rainfall per month for three different regions in the Northwestern United States: Please use SPSS and complete the following:
Plains Mountains. Forest
April 25.2. 13.0 9.7
May 17.1 18.1 16.5
June 18.9. 15.7. 18.1
July 17.3 11.3 13.0
August 16.5 14.0 15.4
Using SPSS, perform an ANOVA test for the hypothesis that there is not the same amount of rainfall in every region in the Northwestern United States with a significance level of 0.02. What are the two degrees of freedom of your test statistic? Please attach your Word file and, in a written analysis, explain what your conclusion is and why
Solution:
Here, we have to use one way analysis of variance or one way ANOVA F test for checking the given claim. The null and alternative hypotheses for this test are given as below:
Null hypothesis: H0: There is a same amount of rainfall in every region in the Northwestern United States.
Alternative hypothesis; Ha: There is not the same amount of rainfall in every region in the Northwestern United States.
We are given
Level of significance = α = 0.02
The SPSS output for this test is given as below:
Descriptives |
||||||||
Rainfall |
||||||||
N |
Mean |
Std. Deviation |
Std. Error |
95% Confidence Interval for Mean |
Minimum |
Maximum |
||
Lower Bound |
Upper Bound |
|||||||
Plains |
5 |
19.0000 |
3.57771 |
1.60000 |
14.5577 |
23.4423 |
16.50 |
25.20 |
Mountains |
5 |
14.4200 |
2.60327 |
1.16422 |
11.1876 |
17.6524 |
11.30 |
18.10 |
Forest |
5 |
14.5400 |
3.28070 |
1.46717 |
10.4665 |
18.6135 |
9.70 |
18.10 |
Total |
15 |
15.9867 |
3.67907 |
.94993 |
13.9493 |
18.0241 |
9.70 |
25.20 |
ANOVA |
|||||
Rainfall |
|||||
Sum of Squares |
df |
Mean Square |
F |
Sig. |
|
Between Groups |
68.137 |
2 |
34.069 |
3.369 |
.069 |
Within Groups |
121.360 |
12 |
10.113 |
||
Total |
189.497 |
14 |
The degrees of freedom for the test statistic F are given as 2 and 12.
The test statistic value for this test is given as F = 3.369.
The P-value for this test is given as 0.069.
P-value > α = 0.02
So, we do not reject the null hypothesis
There is insufficient evidence to conclude that there is not the same amount of rainfall in every region in the Northwestern United States with a significance level of 0.02.