In: Math
Please walk me through SPSS to answer this question...
Consider the data below of inches of rainfall per month for two different regions in the Northwestern United States:
Plains Mountains
April 25.2 13.0
May 17.1 18.1
June 18.9 15.7
July 17.3 11.3
August 16.5 14.0
Using SPSS, perform a two-sample t-test for the hypothesis that there is not the same amount of rainfall in both regions in the Northwestern United States with a significance level of 0.025. What are the degrees of freedom of your test statistic?
Solution:
Here, we have to use two sample t test for the difference between two population means.
Null hypothesis: H0: There is no significant difference in the amount of rainfall in both regions in the Northwestern United States.
Alternative hypothesis: Ha: There is a significant difference in the amount of rainfall in both regions in the Northwestern United States.
H0: µ1 = µ2 versus Ha: µ1 ≠ µ2
We are given
Level of significance = α = 0.025
The required SPSS output for this test is given as below:
Group Statistics |
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Area |
N |
Mean |
Std. Deviation |
Std. Error Mean |
|
Rainfall |
Plains |
5 |
19.0000 |
3.57771 |
1.60000 |
Mountains |
5 |
14.4200 |
2.60327 |
1.16422 |
Independent Samples Test |
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Levene's Test for Equality of Variances |
t-test for Equality of Means |
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F |
Sig. |
t |
df |
Sig. (2-tailed) |
Mean Difference |
Std. Error Difference |
95% Confidence Interval of the Difference |
|||
Lower |
Upper |
|||||||||
Rainfall |
Equal variances assumed |
.177 |
.685 |
2.315 |
8 |
.049 |
4.58000 |
1.97874 |
.01702 |
9.14298 |
Equal variances not assumed |
2.315 |
7.308 |
.052 |
4.58000 |
1.97874 |
-.05926 |
9.21926 |
For this test, the test statistic value is given as t = 2.315.
The degrees of freedom is given as df = 8.
The P-value is given as 0.049.
P-value > α = 0.025
So, we do not reject the null hypothesis
There is insufficient evidence to conclude that there is not the same amount of rainfall in both regions in the Northwestern United States with a significance level of 0.025.