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The data below are yields for two different types of corn seed that were used on...

The data below are yields for two different types of corn seed that were used on adjacent plots of land. Assume that the data are simple random samples and that the differences have a distribution that is approximately normal. Construct a​ 95% confidence interval estimate of the difference between type 1 and type 2 yields. What does the confidence interval suggest about farmer​ Joe's claim that type 1 seed is better than type 2​ seed? Type 1 1988 2014 2190 2478 2208 1983 2258 1504 Type 2 2012 1919 2099 2437 2167 1911 2179 1444 In this​ example, mu Subscript d is the mean value of the differences d for the population of all pairs of​ data, where each individual difference d is defined as the type 1 seed yield minus the type 2 seed yield. The​ 95% confidence interval is 24.66 less thanmu Subscript dless than89.09 . ​(Round to two decimal places as​ needed.) What does the confidence interval suggest about farmer​ Joe's claim that type 1 seed is better than type 2​ seed? A. Because the confidence interval only includes positive values and does not include ​zero, there is sufficient evidence to support farmer​ Joe's claim. This is the correct answer. B. Because the confidence interval includes ​zero, there is sufficient evidence to support farmer​ Joe's claim. C. Because the confidence interval only includes positive values and does not include ​zero, there is not sufficient evidence to support farmer​ Joe's claim. Your answer is not correct. D. Because the confidence interval includes ​zero, there is not sufficient evidence to support farmer​ Joe's claim. Question is complete. Tap on the red indicators to see incorrect answers. All parts showing

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Expert Solution

Obs. Type 1 Type 2 d=Type1-Type2
1 1988 2012 -24 -80.875 6540.76563
2 2014 1919 95 38.125 1453.51563
3 2190 2099 91 34.125 1164.51563
4 2478 2437 41 -15.875 252.015625
5 2208 2167 41 -15.875 252.015625
6 1983 1911 72 15.125 228.765625
7 2258 2179 79 22.125 489.515625
8 1504 1444 60 3.125 9.765625
SUM = 455 10390.875
MEAN = 56.875

milcah answered 1 year ago
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