In: Statistics and Probability
: Students from Elementary school were randomly separated into 4 groups and each group was taught a mathematical concept using a different teaching method. At the end of the teaching period, progress was measured by a unit test. The scores of shown below: (one child in group three was absent on the day the test was administered.)
(1) Construct an ANOVA table
(2) Do the data present significant evidence to indicate a difference in the average scores for the four teaching methods? Tabulated. (critical) F at α .05 = 3.29.
group |
|||
1 |
2 |
3 |
4 |
112 |
111 |
140 |
101 |
92 |
129 |
121 |
116 |
124 |
102 |
130 |
105 |
89 |
136 |
106 |
126 |
97 |
99 |
--- |
119 |
using data >data analysis>ANOVA single Factor
we have
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
1 | 5 | 514 | 102.8 | 218.7 | ||
2 | 5 | 577 | 115.4 | 269.3 | ||
3 | 4 | 497 | 124.25 | 208.25 | ||
4 | 5 | 567 | 113.4 | 105.3 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 1052.682 | 3 | 350.8939 | 1.755669 | 0.198721 | 3.287382 |
Within Groups | 2997.95 | 15 | 199.8633 | |||
Total | 4050.632 | 18 |
(1)
ANOVA | |||||
Source of Variation | SS | df | MS | F | P-value |
Between Groups | 1052.682 | 3 | 350.8939 | 1.755669 | 0.198721 |
Within Groups | 2997.95 | 15 | 199.8633 | ||
Total | 4050.632 | 18 |
(2) since F value 1.756 <3.29 so we conclude that there is no significant evidence to indicate a difference in the average scores for the four teaching methods.