In: Math
Identify two important operating standards that are routinely measured in your organization. These measures must meet the criteria for qualitative, nominal measures. Observations must be cross-classified into a contingency table. Obtain a sample that will produce at least five observations into each group of the cross-classification.
Purpose: To demonstrate the application of non-parametric tests in your organization.
Example: A standard measure that fits these requirements is the human resource department’s employee tracking system. The director of human resources of my company wants to do a study to determine if there is a relationship between the management status and gender of the employees. She creates a contingency table that has Male or Female categories for the rows, and Manager or non-manager categories for the columns. Then she counts the number of female managers, female non-managers, male managers, and male non-managers and enters the numbers in the table. This is the observed value table. Then she conducts the hypothesis test.
a) Perform the cross-classification of the two nominal variables into a contingency table.
b) Test the hypothesis that there is no relationship between the two variables.
c) Discuss the result and interpretation of your hypothesis test
As observed there are 30 males of which 16 are managers and 20 females of which 13 are managers
Then the 2x2 contingency table is given as
Status/Gender | Male | Female | Total |
---|---|---|---|
Manager | 16 | 13 | 29 |
Non manager | 14 | 7 | 21 |
Total | 30 | 20 | 50 |
The expected frequency is Row total * Column total / Grand total
Status/Gender | Male | Female |
---|---|---|
Manager | 17.4 | 11.6 |
Non manager | 12.6 | 8.4 |
B)Null Hypothesis ,H0: There is no relation between gender and management status
Alternative Hypothesis,Ha: There is relationship between gender and management status
Test Statistic is
Oi | Ei | (Oi-Ei) | (Oi-Ei)2 | (Oi-Ei)2/Ei |
---|---|---|---|---|
16 | 17.4 | -1.4 | 1.96 | .11 |
13 | 11.6 | 1.4 | 1.96 | .17 |
14 | 12.6 | 1.4 | 1.96 | .16 |
7 | 8.4 | -1.4 | 1.96 | .23 |
The value of test statistic is .67
Degree of freedom is (r-1)(c-1)= 1
Critical value is 3.841
Since the calculated value is less than critical value , we accept the null hypothesis and conclude that there is no relationship between gender and management status