In: Math
5. People’s Choice, a monthly magazine, claimed that more than 40% of its subscribers had an annual income of $100,000 or more. In a random sample of 62 subscribers, 30 had incomes of $100,000 or more. Using a significance level of 0.10, does this information substantiate the claim of the magazine? Show all test parts to receive full credit. (15 pts)
5. People’s Choice, a monthly magazine, claimed that more than 40% of its subscribers had an annual income of $100,000 or more. In a random sample of 62 subscribers, 30 had incomes of $100,000 or more. Using a significance level of 0.10, does this information substantiate the claim of the magazine? Show all test parts to receive full credit. (15 pts)
One sample proportion test
Ho: P=0.40, H1: P > 0.40
Upper tail test used

sample proportion p=30/62=0.4839

=1.348
Table value of z at 0.10 level = 1.282 (upper tail)
Rejection Region: Reject Ho if z > 1.282
Calculated z = 1.348 falls in the rejection region
The null hypothesis is rejected.
The data provide evidence to support the claim of the magazine that more than 40% of its subscribers had an annual income of $100,000 or more.
| 
 Z Test of Hypothesis for the Proportion  | 
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| 
 Data  | 
|
| 
 Null Hypothesis p =  | 
 0.4  | 
| 
 Level of Significance  | 
 0.1  | 
| 
 Number of Items of Interest  | 
 30  | 
| 
 Sample Size  | 
 62  | 
| 
 Intermediate Calculations  | 
|
| 
 Sample Proportion  | 
 0.4839  | 
| 
 Standard Error  | 
 0.0622  | 
| 
 Z Test Statistic  | 
 1.3480  | 
| 
 Upper-Tail Test  | 
|
| 
 Upper Critical Value  | 
 1.2816  | 
| 
 p-Value  | 
 0.0888  | 
| 
 Reject the null hypothesis  | 
|