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In: Math

5. People’s Choice, a monthly magazine, claimed that more than 40% of its subscribers had an...

5. People’s Choice, a monthly magazine, claimed that more than 40% of its subscribers had an annual income of $100,000 or more. In a random sample of 62 subscribers, 30 had incomes of $100,000 or more. Using a significance level of 0.10, does this information substantiate the claim of the magazine? Show all test parts to receive full credit. (15 pts)

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Expert Solution

5. People’s Choice, a monthly magazine, claimed that more than 40% of its subscribers had an annual income of $100,000 or more. In a random sample of 62 subscribers, 30 had incomes of $100,000 or more. Using a significance level of 0.10, does this information substantiate the claim of the magazine? Show all test parts to receive full credit. (15 pts)

One sample proportion test

Ho: P=0.40, H1: P > 0.40

Upper tail test used

sample proportion p=30/62=0.4839

=1.348

Table value of z at 0.10 level = 1.282 (upper tail)

Rejection Region: Reject Ho if z > 1.282

Calculated z = 1.348 falls in the rejection region

The null hypothesis is rejected.

The data provide evidence to support the claim of the magazine that more than 40% of its subscribers had an annual income of $100,000 or more.

Z Test of Hypothesis for the Proportion

Data

Null Hypothesis            p =

0.4

Level of Significance

0.1

Number of Items of Interest

30

Sample Size

62

Intermediate Calculations

Sample Proportion

0.4839

Standard Error

0.0622

Z Test Statistic

1.3480

Upper-Tail Test

Upper Critical Value

1.2816

p-Value

0.0888

Reject the null hypothesis


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