In: Math
5. People’s Choice, a monthly magazine, claimed that more than 40% of its subscribers had an annual income of $100,000 or more. In a random sample of 62 subscribers, 30 had incomes of $100,000 or more. Using a significance level of 0.10, does this information substantiate the claim of the magazine? Show all test parts to receive full credit. (15 pts)
5. People’s Choice, a monthly magazine, claimed that more than 40% of its subscribers had an annual income of $100,000 or more. In a random sample of 62 subscribers, 30 had incomes of $100,000 or more. Using a significance level of 0.10, does this information substantiate the claim of the magazine? Show all test parts to receive full credit. (15 pts)
One sample proportion test
Ho: P=0.40, H1: P > 0.40
Upper tail test used
sample proportion p=30/62=0.4839
=1.348
Table value of z at 0.10 level = 1.282 (upper tail)
Rejection Region: Reject Ho if z > 1.282
Calculated z = 1.348 falls in the rejection region
The null hypothesis is rejected.
The data provide evidence to support the claim of the magazine that more than 40% of its subscribers had an annual income of $100,000 or more.
Z Test of Hypothesis for the Proportion |
|
Data |
|
Null Hypothesis p = |
0.4 |
Level of Significance |
0.1 |
Number of Items of Interest |
30 |
Sample Size |
62 |
Intermediate Calculations |
|
Sample Proportion |
0.4839 |
Standard Error |
0.0622 |
Z Test Statistic |
1.3480 |
Upper-Tail Test |
|
Upper Critical Value |
1.2816 |
p-Value |
0.0888 |
Reject the null hypothesis |