Question

In: Statistics and Probability

In the summer of 2014, a popular magazine selected a random sample of its subscribers and...

In the summer of 2014, a popular magazine selected a random sample of its subscribers and invited them to vote on its website for their favorite sips of the summer. The results were reported as follows: drink A, 35%; drink B, 30%; drink C, 20%; and drink D, 15%. To test the claim that preference has changed after 5 years, the magazine conducted a similar survey and reported the outcome based on 1,600 randomly selected respondents. The votes for the favorite sips were, 600 for drink A; 420 for drink B; 330 for drink C; and 250 for drink D. Find the value of the test statistic for testing the appropriate hypotheses? Round your answers to the nearest ten-thousandth (4 decimals).

Solutions

Expert Solution

null hypothesis: Ho: preference for favorite sips is same as was stated in 2014.

Alternate hypothesis: Ho: preference for favorite sips has changed from  as was stated in 2014.

degree of freedom =categories-1= 3
for 0.05 level and 3 df :crtiical value X2 = 7.815
Decision rule: reject Ho if value of test statistic X2>7.815
applying chi square goodness of fit test:
           relative observed Expected residual Chi square
category frequency(p) Oi Ei=total*p R2i=(Oi-Ei)/√Ei R2i=(Oi-Ei)2/Ei
A 0.35 600.0 560.00 1.69 2.8571
B 0.30 420.0 480.00 -2.74 7.5000
C 0.20 330.0 320.00 0.56 0.3125
D 0.15 250.0 240.00 0.65 0.4167
total 1.000 1600 1600 11.0863
test statistic X2 = 11.0863
since test statistic falls in rejection region we reject null hypothesis
we have sufficient evidence to conclude that  preference has changed at 5% level of significance

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