In: Chemistry
1) An aqueous solution contains 0.34 M
nitrous acid.
One Liter of this solution could be converted into a buffer by the
addition of:
(Assume that the volume remains constant as each substance is
added.)
0.17 mol HCl
0.35 mol HCl
0.35 mol KNO2
0.086 mol Ca(OH)2
0.34 mol KCl
2)
An aqueous solution contains 0.26 M
ammonium chloride.
One liter of this solution could be converted into a buffer by the
addition of:
(Assume that the volume remains constant as each substance is
added.)
0.25 mol NH3
0.06 mol Ba(OH)2
0.25 mol KCl
0.26 mol HI
0.12 mol HI
Buffer solution is a solution which resists the change in pH.
Buffers are of two types.
1. Acidic buffer
2.Basic buffer
Acidic buffer solution is a mixture of weak acid and salt formed by this weak acid with a strong base.
Similarly basic buffer is a mixture of weak base and salt formed by this weak base with a strong acid.
Number of moles of nitrous acid in 1 L of 0.34 M nitrous acid:
Number of moles of nitrous acid= (0.34 moles/L)*1L = 0.34 moles
Nitrous acid (HNO2 ) is a weak acid. In order to make buffer with nitrous acid, salt of nitrous acid with a strong base is required.
HCl is a strong acid. Hence it cannot form buffer with nitrous acid.
KCl is a salt formed by strong base (KOH) and strong acid (HCl). Hence it cannot form buffer.
Calcium hydroxide is a strong base and when 0.086 moles of calcium hydroxide is added to 0.34 moles of nitrous acid,
0.172 moles Ca(NO2)2 is formed. Hence solution it forms a buffer.
0.35 moles of Potassium Nitrite (salt of strong base (KOH) and weak acid (nitrous acid) is added to 0.34 moles of nitrous acid forms a buffer.
2)
Ammonium chloride is a salt of weak base ( ammonia) and strong acid (HCl).
Number of moles of ammonium chloride in 1 L of 0.26 M solution is 0.26 moles
0.25 moles of aqueous ammonia or ammonium hydroxide with 0.26 moles of ammonium chloride forms basic buffer.
0.26 moles of KCl is a salt of strong base with a strong acid. It cannot form buffer.
HI is a strong acid and it cannot form a buffer.
0.06 moles of Ba(OH)2 also cannot form buffer.