Question

In: Computer Science

python Create a dictionary and insert several English words as keys and the Pig Latin (or...

python

  1. Create a dictionary and insert several English words as keys and the Pig Latin (or any other language) translations as values.

  2. Write a function called bonus that takes as a parameter a dictionary that has names as keys and salaries as values. Your function should increase everyone’s salary in the dictionary by 5%.

  3. Write a function called updateAge that takes as parameters a list of names of people whose birthday it is today, and a dictionary that has names as keys and ages as values. Your function should increment the age in the dictionary of each person whose birthday it is today.

  4. Write a function called seniorList that takes as a parameter a dictionary that has names as keys and class years as values. Your function should return a list of names of students who are graduating in 2020.

  5. Write a function called union that takes as parameters two dictionaries and returns a new dictionary with the entries of both. For common keys, take the value of the first dictionary.

Solutions

Expert Solution

1)def vowel(ch): # this function checks whether a character is a vowel OR NOT

a="AEIOUaeiou"

if ch in a:

return True

return False

def piglatin(s): # THIS CONVERTS ENGLISH WORD TO PIGLATIN

l=len(s)

i=-1

for j in range(len(s)):

if(vowel(s[j])): # CHECKING IF THERE IS VOWEL IN THE STRING

i=j

break

if(i==-1): #IF THERE IS NO VOWEL WE CANNOT CONVERT TO piglatin

return -1

else: #IF POSSIBLE THEN WE ARE SPLITTING AT THE VOWEL AND THE SECOND PART [i:]+ FIRSTPART [0:I]+"ay"

return s[i:]+s[0:i]+"ay"

d={}

l=["Hii","This","is","praneeth"]

for i in l: #FINDING piglatin WORD FOR EACH OF THE WORD IN LIST

res=piglatin(i)

if(res!=-1):

d[i]=res

print(d) #PRINTING DICTIONARY

2)

def bonus(d):

for key,value in d.items():

increased_amount = (value*5)//100 #caluculating increased amount

value+=increased_amount #adding it to the original salary

d[key]=value # changing the salary or updating the salary

return d

d={"Praneeth":10000,"Yeswanth":90000,"vamsi":60000,'vikas':60000}

res=bonus(d) #passing dictionary to bonus function

print(res) #PRINTING DICTIONARY

3)

def updateAge(l,d): #updating age method

for i in l:

age=d[i] #get the values of the person whose birthday is today

age+=1 #assigning and updating the age by one

d[i]=age

return d

d={"praneeth":20,"Yeswnth":90,"vamsi":65,'vikas':103,'krishna':19}

l=['praneeth','krishna']

res=updateAge(l,d)

print(res) #PRINTING DICTIONARY

4)

def seniorList(d): #seniorList method

res=[] #resultant list

for key,value in d.items():

if value==2020: #checking whether a person is graduated in 2020

res.append(key)

return res #returning the list

d={"praneeth":2020,"Yeswnth":2019,"vamsi":1998,'vikas':1030,'krishna':1976}

res=seniorList(d)

print(res) #PRINTING DICTIONARY

5)

def union(d1,d2):

res={}

for key,value in d2.items():

res[key]=value #in this we need not to check if the value is repeated or and for this case we are first adding all the values from the second dictionary then after we should insert elements from first dictionary

for key,value in d1.items():

res[key]=value

return res

d1={"praneeth":2020,"Yeswnth":2019,"vamsi":1998,'vikas':1030,'krishna':1976}

d2={"hiii":12,"praneeth":1000,"ravi":23,"vamsi":222}

res=union(d1,d2)

print(res) #PRINTING DICTIONARY


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