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In: Chemistry

Write chemical equations for the following: Please remember to indicate (s) and (aq) when appropriate Al3+...

Write chemical equations for the following: Please remember to indicate (s) and (aq) when appropriate

Al³⁺ added to 1M NaOH equation...then additional 6M NaOH added

Al³⁺ added to 1M NaOH equation...then additional 15M ammonia added

Al³⁺ added to 1M NaOH equation...then additional 6M HNO₃ added

Al³⁺ added to 1M NH₃ (aq) equation...then additional 6M NaOH added

Al³⁺ added to 1M NH₃ (aq) equation...then additional 15M Ammonia added

Al³⁺ added to 1M NH₃ (aq) equation...then additional 6M HNO₃ added

Ba²⁺ added to 1M Na₂SO₄

Ba²⁺ added to 1M NH₃ (aq)

Ni²⁺ added to 1M NaOH equation...then additional 15M Ammonia added

Ni²⁺ added to 1M NaOH equation...then additional 6M HNO₃ added

Ni²⁺ added to 1M NH₃ equation...then additional 6M NaOH added

Ni²⁺ added to 1M NH₃ equation...then additional 15M Ammonia added

Ni²⁺ added to 1M NH₃ equation...then additional 6M HNO₃ added

Ag⁺ added to 3M NaCl

Ag⁺ added to 1M NaOH equation...then additional 15M Ammonia added

Ag⁺ added to 1M NaOH equation...then additional 6M HNO₃ added

Ag⁺ added to 1M NH₃ equation...then additional 6M NaOH added

Ag⁺ added to 1M NH₃ equation...then additional 15M Ammonia added

Ag⁺ added to 1M NH₃ equation...then additional 6M HNO₃ added

Expert Solution

a. Al³⁺ (aq) + NaOH (aq, 1M) Al(OH)₃ (s) + Na⁺(aq, 1 M)

If you add an additional amount of 6 M NaOH then the equilibrium shifts towards right side, i.e. towards Al(OH)₃.

b. Al³⁺ (aq) + NaOH (aq, 1M) Al(OH)₃ (s) + Na⁺(aq, 1 M)

If you add an additional amount of 15 M ammonia, then NH₃ binds to Al³⁺ to form the soluble complex, i.e [Al(NH₃)₆]³⁺ (aq).

c. Al³⁺ (aq) + NaOH (aq, 1M) Al(OH)₃ (s) + Na⁺(aq, 1M)

If you add an additional amount of 6 M HNO₃ then the soluble Al(NO₃)₃ (aq) forms.

d. Al³⁺ (aq) + NH₃ (aq, 1M) [Al(NH₃)₆]³⁺ (aq)

If you add an additional 6 M NaOH then the formation of Al(OH)₃ (s) and NH₃ (l) takes place.

e. Al³⁺ (aq) + NH₃ (aq, 1M) [Al(NH₃)₆]³⁺ (aq)

If you add an additional amount of 15 M Ammonia then the above reaction won't disturb.

f. Al³⁺ (aq) + NH₃ (aq, 1M) [Al(NH₃)₆]³⁺ (aq)

If you add additional amount of 6M HNO₃ then the formation of Al(NO₃)₃ (aq) takes place along with NH₃ (l).

queen_honey_blossom answered 2 years ago

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