A piano tuner stretches a steel piano wire with a tension of 765 N. The steel wire has a length of 0.800 m and a mass of 6.00 g.

A piano tuner stretches a steel piano wire with a tension of 765 N. The steel wire has a length of 0.800 m and a mass of 6.00 g.

1. What is the frequency f1 of the string's fundamental mode of vibration? (Express your answer numerically in hertz using three significant figures.)

=______ Hz

2.What is the number n of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to f = 16 kHz?

n=_________________

Solutions

Expert Solution

v=frequency*wavelength

for fundamental frequency (first harmonic): wavelength=2L

v=(TL/m)^1/2

(765*.8/.006)^1/2=f*2*.8

f=200 Hz

genius_generous answered 2 years ago

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