In: Physics
Part One: A simple pendulum of length l =0.800 has a mass =0.250kg. What is the tension in the string when it is at angle theta =12.5°? Show your force diagram and work to support your answer.
Part Two: What is the period T of the motion of the pendulum in Part One? Assume the period is independent of angle theta.
(ANS) : Part-1 : Given : l = 0.800 m , m = 0.250 kg . = 12.5 o, g = 9.8 m/ sec2 .Find tension in the string T = ?
Since , T = mg cos (
T = 0.250 x 9.8 x COS(12.50)
T = 2.45 x 0.9762
T = 2.3919 N .
Therefore , the tension in the string is T = 2.3919 N
PART - 2 : From
T = 2x 3.14
T = 6.28 x
T = 6.28 x 0.2856
T = 1.7939 Sec
Therefore , the time period of the motion of pendulam is T = 1.7939 Sec