Question

In: Physics

Part One: A simple pendulum of length l =0.800 has a mass =0.250kg. What is the...

Part One: A simple pendulum of length l =0.800 has a mass =0.250kg. What is the tension in the string when it is at angle theta =12.5°? Show your force diagram and work to support your answer.

Part Two: What is the period T of the motion of the pendulum in Part One? Assume the period is independent of angle theta.

Expert Solution

(ANS) : Part-1 : Given : l = 0.800 m , m = 0.250 kg . = 12.5 ^o, g = 9.8 m/ sec² .Find tension in the string T = ?

Since , T = mg cos (

T = 0.250 x 9.8 x COS(12.5⁰)

T = 2.45 x 0.9762

T = 2.3919 N .

Therefore , the tension in the string is T = 2.3919 N

PART - 2 : From

T = 2x 3.14

T = 6.28 x

T = 6.28 x 0.2856

T = 1.7939 Sec

Therefore , the time period of the motion of pendulam is T = 1.7939 Sec

genius_generous answered 1 year ago

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