In: Statistics and Probability
18. A group of Industrial Organizational psychologists wanted to test if giving a motivational speech at the end of a meeting would encourage office workers to have a higher output to their work based on the numbers of sales each workers made. The group tested 10 participants that were in two conditions where one meeting ended in a motivational speech and another were no motivational speech was given. Here are the number of sales that was produced by the 10 participants for both conditions:
Yes speech: 2, 6, 1, 9, 3, 12, 8, 0, 5, 1
No speech: 3, 0, 5, 10, 1, 8, 2, 1, 9, 11
Use the four steps of hypothesis testing to find out if there is a
significant difference between the two groups, using APA format to
answer the question.
Answer:
The 4 steps of hypothesis testing are:
Step 1 : State null hypothesis and alternative hypothesis.
Step 2 : Compute the test statistics value.
Step 3 :Identify the critical value or the P-value by the tables.
Step 4 : Make a conclusion of the hypothesis.
Step1:
H0 : There is a no significant difference between the two groups.
H1 : There is a significant difference between the two groups.
Symbolically: H0: vs H1:
Step2:
the formula for test statistics is
n1, n2 are sample sizes of two samples, and are sample means and , are sample variances. The means and sample variances can be calculated by using formulas of mean and variance from given data.
Here we use excel output of summary statistics:
Yes speech | No speech | ||
Mean | 4.7 | Mean | 5 |
Standard Error | 1.26535 | Standard Error | 1.316561 |
Median | 4 | Median | 4 |
Mode | 1 | Mode | 1 |
Standard Deviation | 4.001389 | Standard Deviation | 4.163332 |
Sample Variance | 16.01111 | Sample Variance | 17.33333 |
Kurtosis | -0.74015 | Kurtosis | -1.80257 |
Skewness | 0.600416 | Skewness | 0.277145 |
Range | 12 | Range | 11 |
Minimum | 0 | Minimum | 0 |
Maximum | 12 | Maximum | 11 |
Sum | 47 | Sum | 50 |
Count | 10 | Count | 10 |
From this output: n1=10 and n2=10, = 4.7 and =5 , = 16.0111 and = 17.33333
Hence test statistics is
Step3:
Now the critical value for this test is T(crit) = 2.101 ( from table with alpha=0.05 and df= n1+n2-2 = 10+10-2 = 18)
Step4:
Conclusion:
If value of test statistics is greater than critical value then we reject H0. But here value of test statistics is less than critical value (i.e -0.164289 < 2.101 ) hence we Accept H0.
As we accept H0, we conclude that there is a no significant difference between the two groups.
The excel output for two sample t- test (for reference):
t-Test: Two-Sample Assuming Unequal Variances | ||
Yes speech | No speech | |
Mean | 4.7 | 5 |
Variance | 16.01111 | 17.33333 |
Observations | 10 | 10 |
Hypothesized Mean Difference | 0 | |
df | 18 | |
t Stat | -0.16429 | |
P(T<=t) one-tail | 0.435667 | |
t Critical one-tail | 1.734064 | |
P(T<=t) two-tail | 0.871334 | |
t Critical two-tail | 2.100922 |
As our hypothesis is two tailed we used t Critical two tailed. And we accept the H0.