Question

in Python 3, I need to search a dictionary for the matching key while ignoring case of the string and the key. then print the dictionary item in it's original case.

here is the code I have so far but the compiler isn't liking that the name string is lowercase

```
dictionary = {"Dan Smith": {"street":"285 Andover Lane", "city":"Pompano Beach", "state":"FL", "zip":"33060"},"Parker Brady": {"street":"7416 Monroe Ave.", "city":"Windsor", "state":"CT", "zip":"07302"}}

name ="dan smith"

line= dict(filter(lambda item: name.lower() in item[0], dictionary.items()))

print("Street:%5s "% line[name]['street'])
print("City:%5s" % line[name]['city'])
print("State:%5s "% line[name]['state'])
print("Zip Code:%5s "% line[name]['zip'])
```

output should be

Street: 285 Andover Lane

City: Pompano Beach

State: FL

Zip Code: 33060

Answer 1

code:

output :

raw_coode :

#given data
dictionary = {"Dan Smith": {"street":"285 Andover Lane",
"city":"Pompano Beach", "state":"FL",
"zip":"33060"},
"Parker Brady": {"street":"7416 Monroe Ave.",
"city":"Windsor", "state":"CT",
"zip":"07302"}}

name ="dan smith"
#using comprehension for changing to lower case
line = {i.lower(): j for i,j in dictionary.items()}

#displaying required details
print("Street: %5s"%line[name]['street'])
print("City:%5s" % line[name]['city'])
print("State:%5s "% line[name]['state'])
print("Zip Code:%5s "% line[name]['zip'])

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