Question

I have a python dictionary with the following format

Key Type Value

January str ['January 01 2020', 'January 02 2019', 'January 03 2018']

June str ['June 04 2018', 'June 05 2018', 'June 06 2016]

August str ['Augsut 07 2016', 'August 08 2016']

How do return the following conclusion with python code?

January has the most day (1) in 2020

January has the most day (1) in 2019

June has the most days (2) in 2018

August has the most days (2) in 2016

Answer 1

In case of any query do comment. Thanks

Code:

#function to calculate number of days in the given dictionary for the given month as key and year to serach
def findNumbeOfDays(monthsDictionary, key, year):
    count =0
    #if month is present in the dictionary
    if key in monthsDictionary:
        #take out the value part which is a list here
        listValue = monthsDictionary[key]
        #iterate over a list of values
        for item in listValue:
            #find if item in the list contains year given then increase the count
            if year in item:
                count = count +1
    return count


def main():
    #prepare a dictionary as given
    months ={
                'January':['January 01 2020', 'January 02 2019', 'January 03 2018'],
                'June':['June 04 2018', 'June 05 2018', 'June 06 2016'] ,
                'August': ['August 07 2016', 'August 08 2016']
                
            }
    #call findNumbeOfDays function as per the given format print the output
    print("January has the most day ({}) in 2020".format(findNumbeOfDays(months,'January','2020')))
    print("January has the most day ({}) in 2019".format(findNumbeOfDays(months,'January','2019')))
    print("June has the most day ({}) in 2018".format(findNumbeOfDays(months,'June','2018')))
    print("August has the most day ({}) in 2016".format(findNumbeOfDays(months,'August','2016')))
#main driver function
if __name__ == '__main__':
    main()

screen shot of the code for indentation and output: