Question

python pls

create a function party_place: that search the dictionary and figure out where they party in that day.

For example

def party_place(dict2: dict, date: (int,int,int)):

dict1= {'fire1': {(2000,5,20,480) : ('Aaron', 25, 300, ( 0, 300)),
(2000,5,20,720) : ('Baily', 45, 1500, (1500,500)),
(2000,5,21,490) : ('Aaron', 35, 500, (1300,500)) },
'fire2': {(2000,5,20,810) : ('Baily', 45, 1400, (600,1600)),
(2000,5,20,930) : ('Baily', 43, 1800, ( 0, 0)) }}

output

print(party_place(dict1, (2000,5,20,720))

= ['fire1', 'fire2']

print(party_place(dict1, (2000,5,21,720))

= ['fire1']

print(party_place(dict1, (2000,5,22,720))

= []

Answer 1

def party_place(dict2: dict, date: (int, int, int, int)):

    # remove last part

    date = date[:3]

    # list to return

    places = []

    # iterate over dict2

    for place in dict2:

        dates = dict2[place]

        # remove last part from all dates

        dates = [d[:3] for d in dates]

        # if given date is present in current place

        if date in dates:

            # add to places

            places.append(place)

    return places

dict1 = {'fire1': {(2000, 5, 20, 480): ('Aaron', 25, 300, (0, 300)),

                   (2000, 5, 20, 720): ('Baily', 45, 1500, (1500, 500)),

                   (2000, 5, 21, 490): ('Aaron', 35, 500, (1300, 500))},

         'fire2': {(2000, 5, 20, 810): ('Baily', 45, 1400, (600, 1600)),

                   (2000, 5, 20, 930): ('Baily', 43, 1800, (0, 0))}}

print(party_place(dict1, (2000, 5, 20, 720)))  # =['fire1', 'fire2']

print(party_place(dict1, (2000, 5, 21, 720)))  # =['fire1']

print(party_place(dict1, (2000, 5, 22, 720)))  # =[]

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Screenshot:

Output:

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