Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M...

Calculate the volume of 0.820-M NaOH solution needed to completely neutralize 112 mL of a 0.620-M solution of the monoprotic acid HCl.

__________ mL NaOH

Expert Solution

As both NaOH and HCl case, Molarity = Normality

N_base x V_base = N_acid X V_acid

N_base = 0.82 M and V_base = ?

Similarily, N_acid = 0.62 M and V_acid = 112 mL (given)

From above relation: 0.82 X V_base = 0.62 x 112

V_base = 0.62 x 112 / 0.82

V_base = 69.44 / 0.82

V_base = 84.68 mL

queen_honey_blossom answered 2 years ago

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