Question

In: Math

Grades on an english test can be modeled as a normal distribution with mean 80 and...

Grades on an english test can be modeled as a normal distribution with mean 80 and standard deviation 5.

A) if the english department is awarding students with test grades in the top 5%, find the lowest grade a student needs to receive the award.

B) A student is randomly selected from the class so the distribution of this student's test grade is N(80,5), what is the probability that this student scored above a 90?

C) What is the probability that the student in part b scored exactly a 90?

D) If 5 students are randomly selected from the class. what is the probability that exactly 3 of them scored above a 90?

E) If 20 students are randomly selected from the class what is the probability that at least 12 of them scored above an 80?

Solutions

Expert Solution

(a)

(b)

(c)

Since normal distribution is continuous distribution so the probability exactly at one point is zero so the probability that the student in part b scored exactly a 90 is

P(X =90) = 0

(d)

Here we need to use binomial distribution with parameter n=5 and p=0.0228 (from part b). The  probability that exactly 3 of them scored above a 90 is

(e)

----------------------------------------------------------

Now we need to use binomial distribution with parameter n=20 and p=0.5. The  probability that at least 12 of them scored above an 80 is


Related Solutions

The lifetime of a particular brand of tire is modeled with a normal distribution with mean...
The lifetime of a particular brand of tire is modeled with a normal distribution with mean μ = 75,000 miles and standard deviation σ = 5,000 miles. a) What is the probability that a randomly selected tire lasts less than 67,000 miles? b) If a random sample of 35 tires is taken, what is the probability that the sample mean is greater than 70,000 miles?
A distribution of values is normal with a mean of 80 and a standard deviation of...
A distribution of values is normal with a mean of 80 and a standard deviation of 18. From this distribution, you are drawing samples of size 12. Find the interval containing the middle-most 88% of sample means: Enter your answer using interval notation. In this context, either inclusive or exclusive intervals would be acceptable. Your numbers should be accurate to 1 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
A distribution of values is normal with a mean of 80 and a standard deviation of...
A distribution of values is normal with a mean of 80 and a standard deviation of 18. From this distribution, you are drawing samples of size 13. Find the interval containing the middle-most 32% of sample means: Incorrect Enter your answer using interval notation. In this context, either inclusive or exclusive intervals would be acceptable. Your numbers should be accurate to 1 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
The flow in a river can be modeled as a log-normal distribution. From the data, it...
The flow in a river can be modeled as a log-normal distribution. From the data, it was estimated that, the probability that the flow exceeds 1100 cfs is 50% and the probability that it exceeds 100 cfs is 90%. Let X denote the flow in cfs in the river. Flood conditions occur when flow is 5000 cfs or above. To compute the percentage of time flood conditions occur for this river, we have to find, P(X≥5000)=1-P(Z<a). What is the value...
2. The hardness of some cement samples can be modeled by a normal distribution with an...
2. The hardness of some cement samples can be modeled by a normal distribution with an average of 6,000 kg / cm2 and a standard deviation of 1000 kg / cm2. a) What is the probability that the hardness of the sample is less than 6.250 kg / cm2? b) What is the probability that the hardness of the sample is between 5,800 and 5,900 kg / cm2? c) Which value is exceeded by 90% of the hardness? d) Among...
The monthly returns for a financial advisory service can be modeled by a Normal distribution with...
The monthly returns for a financial advisory service can be modeled by a Normal distribution with a mean of $145 and standard deviation of $79, per $10,000 invested. Find the following boundaries: (use 5 decimals for all answers) PLEASE SHOW ALL WORK AND CALCULATIONS PLEASE AND THANK YOU 1. the highest 20% of monthly returns is _____ 2. the lowest 20% of monthly returns is ______ 3. the highest 10% of monthly returns is _______ 4. the middle 20% of...
The monthly returns for a financial advisory service can be modeled by a Normal distribution with...
The monthly returns for a financial advisory service can be modeled by a Normal distribution with a mean of $119 and standard deviation of $91, per $10,000 invested. Find the following boundaries: (use 4 decimals for all answers) (a) the highest 10% of monthly returns:_______ (b) the lowest 10% of monthly returns: _______ (c) the highest 20% of monthly returns: _________ (d) the middle 60% of monthly returns: _______ and________ (Enter the lower value first.)
The test grades in some class follow a normal distribution (we will call it X) with...
The test grades in some class follow a normal distribution (we will call it X) with σ = 8. Use this information (and the chart!) to answer the following questions: (a) If there is a 60% chance that a student scores higher than a 75, find µ, the average test grade for this class. (b) Using the µ you found in part (a), determine P(72 ≤ X ≤ 90).
8) Scores on an exam have a normal distribution with a mean of 80 and a...
8) Scores on an exam have a normal distribution with a mean of 80 and a standard deviation of 12. a) Find the probability that a person would score above 90. b) Find the probability that a person would score between 75 and 85. c) Find the probability that a group of 7 people would have a mean score above 84. d) Find the score needed to be in the top 10% of the class.
The distribution of scores on a recent test closely followed a Normal Distribution with a mean...
The distribution of scores on a recent test closely followed a Normal Distribution with a mean of 22 points and a standard deviation of 2 points. For this question, DO NOT apply the standard deviation rule. (a) What proportion of the students scored at least 21 points on this test, rounded to five decimal places? (b) What is the 63 percentile of the distribution of test scores, rounded to three decimal places?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT