In: Physics
For my lab report, i was asked to find the volume uncertainty of different cylinders:
Length m |
Diameter m (r = d/2) |
|
A |
0.0407 ± 0.00025 m |
0.0179 ± 0.0005 m |
B |
0.0377 ± 0.00025 m |
0.0317 ± 0.0005 m |
C |
0.0361 ± 0.00025 m |
0.019 ± 0.0005 m |
D |
0.0462 ± 0.00025 m |
0.0158 ± 0.0005 m |
E |
0.0339 ± 0.00025 m |
0.019 ± 0.0005 m |
in the table below, its the volume but what I NEED IS ITS UNCERTAINTY:
V = (PI)(r)(h)
Cylinders |
Volume convert to m^3 and find the uncertainty |
A |
1.024 * 10^-5 |
B |
2.975 * 10^-5 |
C |
1.023 * 10^-5 |
D |
9.05 * 10^-6 |
E |
9.61 * 10^-6 |
first go through the image to understand the concept
in case 3
cylinder C
Percentage uncertainty in the length = (0.00025/0.0361) x 100 =
0.070
Percentage uncertainty in the diameter= (0.0005/0.019) x 100 =
2.631
% uncertainty = 0.070 + 2.631 = 2.701
volume = 1.023 *10^-5
Absolute uncertainty in volume = (1.023*10^-5/100) x2.701 =
0.0000002763
case 4
cylinder D
Percentage uncertainty in the length = (0.00025/0.0462) x 100 =
0.541
Percentage uncertainty in the diameter= (0.0005/0.0158) x 100 =
3.164
% uncertainty = 0.541 + 3.164 = 3.705
volume = 9.05 *10^-6
Absolute uncertainty in volume = (9.05*10^-6/100) x3.705 =
0.0000003353
case 5
cylinder D
Percentage uncertainty in the length = (0.00025/0.0339) x 100 =
0.737
Percentage uncertainty in the diameter= (0.0005/0.019) x 100 =
2.631
% uncertainty = 0.737 + 2.631 = 3.368
volume = 1.023 *10^-5
Absolute uncertainty in volume = (9.61*10^-6/100) x3.368 =
0.0000003237