In: Math
The average number of people in a family that received welfare for various years is given below.
| YEAR | Welfare family size |
| 1969 | 4.0 |
| 1973 | 3.6 |
| 1975 | 3.2 |
| 1979 | 3.0 |
| 1983 | 3.0 |
| 1988 | 3.0 |
| 1991 | 2.9 |
y=88.721+ -0.043x
part d.
Find the estimated welfare family size in 1970. (Use your equation from part (b). Round your answer to one decimal place.) _______ people.
Find the estimated welfare family size in 1989. (Use your
equation from part (b). Round your answer to one decimal
place.)
_______ people.
Use the two points in part (d) to plot the least squares line. (Upload your file below.)
Given that y = 88.721+ -0.043x
x = 1970 then
y = 88.721+ -0.043 ( 1970 ) = 4.0
x = 1989 then
y = 88.721+ -0.043 ( 1989 ) = 3.2
Now the new data is
| Year | Welfare family size |
| 1969 | 4 |
| 1973 | 3.6 |
| 1975 | 3.2 |
| 1979 | 3 |
| 1983 | 3 |
| 1988 | 3 |
| 1991 | 2.9 |
| 1970 | 4 |
| 1989 | 3.2 |
for above data regression output is
| SUMMARY OUTPUT | ||||||
| Regression Statistics | ||||||
| Multiple R | 0.834705358 | |||||
| R Square | 0.696733035 | |||||
| Adjusted R Square | 0.653409183 | |||||
| Standard Error | 0.256241497 | |||||
| Observations | 9 | |||||
| ANOVA | ||||||
| df | SS | MS | F | Significance F | ||
| Regression | 1 | 1.055937622 | 1.055938 | 16.08197 | 0.005122786 | |
| Residual | 7 | 0.459617934 | 0.06566 | |||
| Total | 8 | 1.515555556 | ||||
| Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
| Intercept | 88.52892788 | 21.24748909 | 4.16656 | 0.004207 | 38.28659991 | 138.77126 |
| X Variable 1 | -0.043040936 | 0.010732775 | -4.01023 | 0.005123 | -0.068419916 | -0.017662 |
from above output now regression equation is
Welfare family size = 88.529 + (- 0.043 year )