Question

In: Computer Science

write a c++ program an expression that determines if an integer, n is a negative four...

write a c++ program an expression that determines if an integer, n is a negative four digit number.

write a c++ program an expression that determines if a string, wd, equals "so" ignoring case.

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Expert Solution

Here are the answers for your questions in C++ Programming Language.

Kindly upvote if you find the answer helpful.

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CODE :

Question : write a c++ program an expression that determines if an integer, n is a negative four digit number.

#include<iostream>

using namespace std;

int main(){
   //Required variable
   int n;
  
   //Read value from user(assuming user eners valid value)
   cout << "Enter an integer: ";
   cin >> n;
  
   //Expression to determine if 'n' is a negaive four digit number
   if(n >= -9999 && n <= -1000){
       cout << "Given integer " << n << " is a negative four digit number." << endl;
   }else{
       cout << "Given integer " << n << " is NOT a negative four digit number." << endl;
   }
   return 0;
}

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SCREENSHOTS :

Please see the screenshots of the code below for the indentations of the code.

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OUTPUT :

#########################################################################

CODE :

Question : write a c++ program an expression that determines if a string, wd, equals "so" ignoring case.

#include<iostream>
#include<strings.h>

using namespace std;

int main(){
   //Required variable
   string wd;
  
   //Reading input from user
   cout << "Enter a string: ";
   cin >> wd;
  
   //Expression to determise the string wd equals 'so' ignoring case
   if(strcasecmp(wd.c_str(),"so")== 0){
       cout << "Given string equals 'so'." << endl;
   }else{
       cout << "Given string doesn't equal 'so'." << endl;
   }
   return 0;
}

####################################################################

SCREENSHOTS :

Please see the screenshots of the code below for the indentations of the code.

########################################################################

OUTPUT :

Any doubts regarding this can be explained with pleasure :)


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