Question

Write a program that reads n integer values. If a negative value is entered, we want to terminate the input, i.e., exit from the loop. If a zero value is entered, we want to ignore it and read the next value. Any strictly positive values (greater or equal zero) are to be totaled. Print the number of values read, the number of values totaled and the total. If a negative value is entered, print an error message before terminating the loop.

write in c plus plus

Answer 1

Program in C++ with comments using a do while loop with break statement fo negative integer.

#include <iostream>

using namespace std;

int main() {
//variables to count initiated to 0
int count=0, countNumbers =0,total =0,value;
//loop to read integers till break is executed
do{
cout<<"\nEnter a number: ";
cin>>value;
//once value is read increase value read count
count++;
//if value is negative display error and break from the loop
if(value<0){
cout<<"\nError!!Negative value entered!Program will terminate";
break;
}
//if value is 0 ignore it
else if(value==0){
//add count of positive numbers
countNumbers++;
}
//if value is positive increase count of numbers and add it to total
else {
countNumbers++;
total +=value;
}

}while(true);
//display all the values counted
cout << "\nNumber of values read is "<<count;
cout << "\nNumber of values totaled is "<<countNumbers;
cout << "\nTotal of values is "<<total;
}

Sample output :