Question

In: Math

   Ovservation   Portland   Houston   Jacksonville      1 85 71 64      2 75 75 69     ...

   Ovservation   Portland   Houston   Jacksonville  
   1 85 71 64  
   2 75 75 69  
   3 82 73 67  
   4 76 74 74  
   5 71 69 80  

6 85 82 72

National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To measure employee knowledge of Total Quality Management (TQM), six employees were randomly selected at each plant and tested. The test scores for these employees are given in DATA. Managers want to know if, on average, knowledge of TQM is equal across the 3 plants. Test equality of mean scores at Alpha = 0.05 .

What is the F value? p value? F critical value?

Do we reject equality mean or not? Is knowledge of TQM equal across all 3 plants or not?


  
                  

Solutions

Expert Solution

Using Minitab software, (Stat -> ANOVA -> One way), we get the following output :

Now,

The value of F test statistic = 3.42

P-value = 0.06

and critical value =

Since and P-value > 0.05, so we reject H0 at 5% level of significance and we can conclude that there is no significant difference in means of knowledge of TQM among 3 plants.


Related Solutions

National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To...
National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To measure employee knowledge of Total Quality Management (TQM), six employees were randomly selected at each plant and tested. The test scores for these employees are given in DATA. Managers want to know if, on average, knowledge of TQM is equal across the 3 plants. Test equality of mean scores at x = 0.05 Ovservation Portland Houston Jacksonville 1 85 71 64 2 75 75...
57, 69, 70, 71, 74, 77, 79, 80, 80, 80, 80, 81, 81, 82, 85, 85,...
57, 69, 70, 71, 74, 77, 79, 80, 80, 80, 80, 81, 81, 82, 85, 85, 86, 88, 91, 95, 95, 100 1) Create a relative frequency table for these data. 2) Create a histogram for these data and comment on the shape of the distribution (skewed, symmetric, etc). 3) Create a boxplot for the data (you’ll need to report the median, quartiles, and outliers).
obs gpa iq gender concept 1 7.94 121 2 69 2 8.292 120 2 71 3...
obs gpa iq gender concept 1 7.94 121 2 69 2 8.292 120 2 71 3 4.643 111 2 44 4 7.47 106 2 44 5 8.882 108 1 69 6 7.585 98 2 72 7 7.65 121 2 53 8 2.412 75 2 26 9 6 109 1 47 10 8.833 122 2 64 11 7.47 109 1 46 12 5.528 106 1 62 13 7.167 105 2 53 14 7.571 89 1 68 15 4.7 85 1 62...
Gender Year CompAtt SelfEffi 2 2 55 90 1 3 65 71 1 4 74 75...
Gender Year CompAtt SelfEffi 2 2 55 90 1 3 65 71 1 4 74 75 1 4 60 55 1 4 73 88 2 3 80 60 1 3 79 65 2 4 84 66 1 4 57 67 2 3 60 69 2 3 75 75 1 4 73 88 2 3 50 60 2 3 80 65 2 4 82 66 2 4 68 67 2 3 70 69 2 3 67 75 2 3 72 80...
The actual values for 12 periods (shown in order) are: (1) 45 (2) 52 (3) 48 (4) 59 (5) 55 (6) 58 (7) 64 (8) 61 (9) 71 (10) 66 (11) 69 (12) 77
Question 1 contains the actual values for 12 periods (listed in order, 1-12). In Excel, create forecasts for periods 6-13 using each of the following methods: 5 period simple moving average; 4 period weighted moving average (0.63, 0.26, 0.08, 0.03); exponential smoothing (alpha = 0.23 and the forecast for period 5 = 53); linear regression with the equation based on all 12 periods; and quadratic regression with the equation based on all 12 periods. Round all numerical answers to two...
The actual values for 12 periods (shown in order) are: (1) 45 (2) 52 (3) 48 (4) 59 (5) 55 (6) 58 (7) 64 (8) 61 (9) 71 (10) 66 (11) 69 (12) 77
Question 1 contains the actual values for 12 periods (listed in order, 1-12). In Excel, create forecasts for periods 6-13 using each of the following methods: 5 period simple moving average; 4 period weighted moving average (0.63, 0.26, 0.08, 0.03); exponential smoothing (alpha = 0.23 and the forecast for period 5 = 53); linear regression with the equation based on all 12 periods; and quadratic regression with the equation based on all 12 periods.  Round all numerical answers to two...
Index 1 2 3 4 5 6 7 Temperature (F) 72 71 78 75 81 77...
Index 1 2 3 4 5 6 7 Temperature (F) 72 71 78 75 81 77 68 Pair of Gloves 37 37 32 36 33 35 39 Taking temperature as an independent variable and pairs of gloves produced as a dependent variable, compute the least square’s regression line.
person weight before diet weight after diet 1 68 64 2 88 86 3 85 83...
person weight before diet weight after diet 1 68 64 2 88 86 3 85 83 4 89 86 5 92 90 The weights of a random sample of 5 people are recorded before they are introduced to the liquid protein diet (a new weight-reducing technique). Then they were instructed to follow the liquid protein diet for 3 weeks. At the end of this period, their weights (in kilograms) are again recorded. Results are given in the table: Person Weight...
0 0.5 1.2 2 2.5 3 3.5 4 4.5 5.5 63 66 69 75 78 81...
0 0.5 1.2 2 2.5 3 3.5 4 4.5 5.5 63 66 69 75 78 81 84 87 90 96 A survey asked students for their college and their satisfaction with their program. The results are provided in the tables below. Determine if there is a relationship between college and satisfaction at the 0.05 level of significance. H0: College and Satisfaction are independent. Ha: College and Satisfaction are dependent. Determine the critical value from the chart. Explain what chart you...
WACC = 8% Period Project 1 Project 2 0 -$175 -$43 1 $75 $30 2 $75...
WACC = 8% Period Project 1 Project 2 0 -$175 -$43 1 $75 $30 2 $75 $90 3 $150 4 5 6 Based on the information in the table, what is the replacement chain NPV for Project 1?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT