Question

In: Statistics and Probability

0 0.5 1.2 2 2.5 3 3.5 4 4.5 5.5 63 66 69 75 78 81...

0 0.5 1.2 2 2.5 3 3.5 4 4.5 5.5
63 66 69 75 78 81 84 87 90 96

A survey asked students for their college and their satisfaction with their program. The results are provided in the tables below.

Determine if there is a relationship between college and satisfaction at the 0.05 level of significance.

H0: College and Satisfaction are independent.

Ha: College and Satisfaction are dependent.

Determine the critical value from the chart. Explain what chart you used and how you found the value.

Determine the test statistic from your calculator. Explain what test you used in the calculator and the information you entered into the calculator.

Using your critical value and test statistic, state your conclusion. Explain how you arrived at your conclusion.

What is the conclusion in context?

Solutions

Expert Solution

df = (6-1)*(2-1)= 5

The critical value from the chart is 11.070.

The Chi-square test is used here.

The test statistic is 6.67.

Since 6.67 < 11.070, we fail to reject the null hypothesis.

Therefore, we can conclude that college and Satisfaction are independent.

Col 1   Col 2   Total  
Row 1 Observed   5 2 7
Expected   4.11 2.89 7.00
O - E   0.89 -0.89 0.00
(O - E)² / E   0.19 0.28 0.47
Row 2 Observed   6 1 7
Expected   4.11 2.89 7.00
O - E   1.89 -1.89 0.00
(O - E)² / E   0.87 1.24 2.11
Row 3 Observed   14 12 26
Expected   15.25 10.75 26.00
O - E   -1.25 1.25 0.00
(O - E)² / E   0.10 0.15 0.25
Row 4 Observed   18 12 30
Expected   17.60 12.40 30.00
O - E   0.40 -0.40 0.00
(O - E)² / E   0.01 0.01 0.02
Row 5 Observed   10 4 14
Expected   8.21 5.79 14.00
O - E   1.79 -1.79 0.00
(O - E)² / E   0.39 0.55 0.94
Row 6 Observed   8 12 20
Expected   11.73 8.27 20.00
O - E   -3.73 3.73 0.00
(O - E)² / E   1.19 1.68 2.87
Total Observed   61 43 104
Expected   61.00 43.00 104.00
O - E   0.00 0.00 0.00
(O - E)² / E   2.76 3.91 6.67
11.070 critical value
6.67 chi-square
5 df
.2466 p-value

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