Question

In: Statistics and Probability

National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To...

National Bearings manufactures bearings at plants located in Portland Oregon, Houston Texas, and Jacksonville Florida. To measure employee knowledge of Total Quality Management (TQM), six employees were randomly selected at each plant and tested. The test scores for these employees are given in DATA. Managers want to know if, on average, knowledge of TQM is equal across the 3 plants. Test equality of mean scores at x = 0.05

Ovservation Portland Houston Jacksonville
1 85 71 64
2 75 75 69
3 82 73 67
4 76 74 74
5 71 69 80
6 85 82 72

A. none of the answers are correct

B. Equality of means is not rejected with pvalue 0.295. Knowledge of TQM is equal across the 3 plants.

C. Equality of means in not rejected with pvalue of 0.060. Knowledge of TQM is equal across the 3 plants.

D. Equality of means is rejected with pvalue 0.010. Knowledge of TQM is not equal across the 3 plants.

E. Equality of means is rejected with pvalue 0.003. Knowledge of TQM is not equal across the 3 plants

Solutions

Expert Solution

Consider

: Average Knowledge of TQM at Portland plant.

: Average Knowledge of TQM at Houston plant.

: Average Knowledge of TQM at Jacksonville plant.

We have to testing the hypothesis

Whether or not Average Knowledge of TQM is equal across the plants ?

i.e Null Hypothesis -

against

Alternative Hypothesis- Ha : Knowledge of TQM is not equal across the 3 plants.

By using Excel

Observation Portland Houston Jacksonville
1 85 71 64 Anova: Single Factor
2 75 75 69
3 82 73 67 SUMMARY
4 76 74 74 Groups Count Sum Average Variance
5 81 69 80 Column 1 6 484 80.66667 18.66667
6 85 82 72 Column 2 6 444 74 20
Column 3 6 426 71 32
ANOVA
Source of Variation SS df MS F P-value F crit
Between Groups 293.7778 2 146.8889 6.235849 0.010692 3.68232
Within Groups 353.3333 15 23.55556
Total 647.1111 17

Alpha : level of significance = 0.05

From excel output p-value = 0.01062

Since p-value < level of significance alpha.

We reject the null Hypothesis at 5% level of significance.

Correct Answer : D - Equality of means is rejected with p-value 0.010. Knowledge of TQM is not equal across the 3 plants.


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