In: Statistics and Probability
Thirteen internists in the Midwest are randomly selected, and
each internist is asked to report last year’s income. The incomes
obtained are
229,000 184,000 141,000 140,000 247,000
215,000 157,000 167,000 139,000 176,000
117,000 221,000 169,000
(a) Find the 90th percentile.
90th percentile $
(b) Find the median.
Median $
(c) Find the first quartile.
First quartile $
(d) Find the third quartile.
Third quartile $
(e) Find the 10th percentile.
10th percentile $
(f) Find the interquartile range.
Interquartile range $
(g-1) Develop a five-number summary.
Income | |
Minimum | $ |
1st quartile | $ |
Median | $ |
3rd quartile | $ |
Maximum | $ |
(g-2) Choose a box plot of this data.
a) Using Excel function percentile
90th percentile = percentile(data, 0.9)
90th percentile = $
227,400
b) Using Excel function median
Median = median(data)
Median = $ 169,000
c) First Quartile is the 25th percentile
Using Excel function percentile
First quartile = percentile(data, 0.25)
First quartile = $ 141,000
d) Third Quartile is the 75th percentile
Using Excel function percentile
Third quartile = percentile(data, 0.75)
Third quartile = $
215,000
e) Using Excel function percentile
10th percentile = percentile(data, 0.1)
10th percentile = $
139,200
f) Interquartile range = Third Quartile - First
Quartile
= 215000 - 141000
= 74000
Interquartile range = $
74,000
g-1) Using Excel function min and max we
get
Minimum = min(data)
= $ 117,000
Maximum = max(data)
= $ 247,000
From all above calculations, the five-number summary
is
g-2) Box plot
Note to student : Since you have not provided the
options, you may choose the option closest
to the boxplot given below
Horizontal Box Plot
OR
Vertical Box plot