Question

The program should be able to do the following: In Java

1. accepts one command line parameter. The parameter specifies the path to a text file containing the integers to be sorted. The structure of the file is as follows:

   1. There will be multiple lines in the file (number of lines unknown).

   2. Each line will contain multiple integers, separated by a single whitespace.

2. reads the integers from the text file in part a into an array of integers.

3. sort the integers in ascending order, and then prints out a sorted version of these integers, one per line

4. Implements the selection sort algorithm.

Answer 1

Code

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;

public class Main {
public static void main(String[] args)
{
int []arr=new int[1000];
int count=0;
String line;
BufferedReader reader;
try
{
reader = new BufferedReader(new FileReader(args[0]));
line = reader.readLine();
while (line != null)
{   
// read next line
String []value=line.split(" ");
for(int i=0;i<value.length;i++)
{
arr[count]=Integer.parseInt(value[i]);
count++;
}
       line = reader.readLine();
}
reader.close();
   }
catch (IOException e)
{
System.out.println(args[1]+" file not found.");
   }
System.out.println("Original Array is: ");
printArray(arr,count);
selectionSort(arr, count);
System.out.println("\n\nAfter sorting array is: ");
printArray(arr,count);
}
public static void selectionSort(int[] arr,int size)
{
for (int i = 0; i < size - 1; i++)
{
int index = i;
for (int j = i + 1; j < size; j++){
if (arr[j] < arr[index]){
index = j;//searching for lowest index
}
}
int smallerNumber = arr[index];   
arr[index] = arr[i];
arr[i] = smallerNumber;
}
}

private static void printArray(int[] arr, int count)
{
for(int i=0;i<count;i++)
System.out.println(arr[i]);
}
}
Numbers.txt file

output

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