Question

Complete the function ConvertToDecadesAndYears to convert totalYears to decades and years. Return decades and years using the ElapsedDecadesYears struct. Ex: 26 years is 2 decades and 6 years.

#include <iostream>
using namespace std;

struct ElapsedDecadesYears {
   int decadesVal;
   int yearsVal;
};

ElapsedDecadesYears ConvertToDecadesAndYears(int totalYears) {
   ElapsedDecadesYears tempVal;

   /* Your code goes here */

}

int main() {
   ElapsedDecadesYears elapsedYears;
   int totalYears;

   cin >> totalYears;

   elapsedYears = ConvertToDecadesAndYears(totalYears);

   cout << elapsedYears.decadesVal << " decades and " << elapsedYears.yearsVal << " years" << endl;

   return 0;
}

Answer 1

• Number of decades that can be fit into a year is the quotient of that year when divided by 10.
• Number of remaining years that after the decades in a year is the remainder of that year when divided by 10.

Code screenshot:

Output:

Code to copy:

#include <iostream>
using namespace std;

struct ElapsedDecadesYears {
int decadesVal;
int yearsVal;
};

ElapsedDecadesYears ConvertToDecadesAndYears(int totalYears) {
ElapsedDecadesYears tempVal;
// we can initialize the value of decadesVal with quotient of totalYears / 10
tempVal.decadesVal = totalYears/10;
// we can initialize the value of yearsVal with remainder of totalYears % 10
tempVal.yearsVal = totalYears%10;
// now we can return the structure object tempVal
return tempVal;
}

int main() {
ElapsedDecadesYears elapsedYears;
int totalYears;
cin >> totalYears;
elapsedYears = ConvertToDecadesAndYears(totalYears);
cout << elapsedYears.decadesVal << " decades and " << elapsedYears.yearsVal << " years" << endl;
return 0;
}