Question

Smaller index

Complete the following function according to its docstring using a while loop. The lists we test will not all be shown; instead, some will be described in English. If you fail any test cases, you will need to read the description and make your own test.

def smaller_index(items):
""" (list of int) -> int
  
Return the index of the first integer in items that is less than its index,
or -1 if no such integer exists in items.
  
>>> smaller_index([2, 5, 7, 99, 6])
-1
>>> smaller_index([-5, 8, 9, 16])
0
>>> smaller_index([5, 8, 9, 0, 1, 3])
3
"""

Answer 1

def smaller_index(items):

    """ (list of int) -> int    

    Return the index of the first integer in items that is less than its index,

    or -1 if no such integer exists in items.

    >>> smaller_index([2, 5, 7, 99, 6])

    -1

    >>> smaller_index([-5, 8, 9, 16])

    0

    >>> smaller_index([5, 8, 9, 0, 1, 3])

    3

    """

    # iterate over items

    for i in range(len(items)):

        # found

        if items[i] < i:

            return i

    # not found

    return -1

# testing

print(smaller_index([2, 5, 7, 99, 6]))

print(smaller_index([-5, 8, 9, 16]))

print(smaller_index([5, 8, 9, 0, 1, 3]))

.

Screenshot:

Output:

.