What is the pH of 1.05 M Cu(NO3)2 ? Ka=3 x 10^-8 Ka is a acid.

Expert Solution

Cu2+ (aq) + 6 H2O (l) ------------> [Cu(H2O)6]2+ (aq)

[Cu(H2O)6]2+ (aq) + H2O (l) -------------> [Cu(H2O)5. OH]+ (aq) + H3O+ (aq)

1.05 0 0

1.05 - x x x

Ka = x^2 / 1.05 - x

3.0 x 10^-8 = x^2 / 1.05 - x

x = 1.775 x 10^-4

[H3O+] = 1.775 x 10^-4 M

pH = -log (H3O+)

= - log (1.775 x 10^-4 )

pH = 3.75

queen_honey_blossom answered 2 years ago

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