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When 200. mL of 0.40 M hydrochloric acid solution is mixed with 3.76 g of aluminum...

When 200. mL of 0.40 M hydrochloric acid solution is mixed with 3.76 g of aluminum metal, how many moles of hydrogen gas would be produced?

6HCl(aq) + 2Al(s) → 2AlCl3(aq) + 3H2(g)

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queen_honey_blossom answered 1 year ago
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