In: Math
Calculate the mean, ?⎯⎯⎯,x¯, and standard deviation, ?,s, for the data set.
Sample | Value |
---|---|
1 | 8.013 |
2 | 8.013 |
3 | 8.012 |
4 | 8.029 |
5 | 8.013 |
6 | 8.025 |
Solution:
Given that,
x | x2 |
8.013 | 64.2082 |
8.013 | 64.2082 |
8.012 | 64.1921 |
8.029 | 64.4648 |
8.013 | 64.2082 |
8.025 | 64.4006 |
x =48.105 | x2 =385.6821 |
The sample mean is
Mean = (x / n)
= (8.013 +8.013 +8.012+8.029+8.013+8.025 / 6 )
= 48.105 /6
= 8.0175
Mean = 8.0175
The sample standard deviation is S
S = ( x2 ) - (( fx)2 / n ) / 1 -n )
= ( 385.6821 ( (48.105 )2 / 6 ) / 5
= ( 385.6821 - 385.6818 / 5 )
= (0.0003 / 5 )
= 0.0001
=0.0075
The sample standard deviation is = 0.0075