In: Math
Calculate the mean, ?⎯⎯⎯,x¯, and standard deviation, ?,s, for the data set.
| Sample | Value |
|---|---|
| 1 | 8.013 |
| 2 | 8.013 |
| 3 | 8.012 |
| 4 | 8.029 |
| 5 | 8.013 |
| 6 | 8.025 |
Solution:
Given that,
| x | x2 |
| 8.013 | 64.2082 |
| 8.013 | 64.2082 |
| 8.012 | 64.1921 |
| 8.029 | 64.4648 |
| 8.013 | 64.2082 |
| 8.025 | 64.4006 |
x
=48.105 |
x2
=385.6821 |
The sample mean is
Mean
= (
x
/ n)
= (8.013 +8.013 +8.012+8.029+8.013+8.025 / 6 )
= 48.105 /6
= 8.0175
Mean
= 8.0175
The sample standard deviation is S
S =
(
x2 ) - ((
fx)2 / n ) / 1 -n )
=
( 385.6821 ( (48.105 )2 / 6 ) / 5
=
( 385.6821 - 385.6818 / 5 )
=
(0.0003 / 5 )
=
0.0001
=0.0075
The sample standard deviation is = 0.0075