In: Chemistry
Show how would you prepare a solution of 500 ml of a 0.15 M acetate buffer. You have available the following: 6M HCl, 4 M acetic, solid sodium acetate, solid sodium hydroxide
in the question, pH = 4.6
pH of acidic buffer = pka + log(sodiumacetate/acetic acid)
pka of aceticacid = 4.76
pH = 4.6
no of mol of buffer = 500*0.15/1000 = 0.075 mol
4.6 = 4.76+log(x/(0.075-x))
x = 0.03067 mol
no of mole of sodium acetate = x = 0.03067 mol
mass of sodium acetate must take = x*Mwt
= 0.03067*82
= 2.515 g
no of mole of aceticacid = 0.075-x
= 0.075-0.03067
= 0.0443 mol
volume of aceticacid = n/M = 0.0443/6*1000 = 7.383 ml
so that, take 7.383 ml of 6M aceticacid and 2.515 grams of sodium acetate and dissolve it in minimum water,then add water up to 500 ml.