In: Physics
The resistance of the wire is
R = ?L/(?r^2)
Here ? = 1.72 x 10-8 ?/m
L = (19)(?d)
= (19)(?(2.80x 10^-3 m))
= 0.167 m
r = (2.80 x 10^-3 m)/2
= 1.40 x 10^-3 m
R = ?L/(?r^2)
= ( 1.72 x 10-8 ?/m) (0.167 m)/(?( 1.40 x 10^-3 m)^2)
= 4.66x 10^-4 ?
The formula for the induced emf is
e =- NA (?B/?t)
=- (19)(?(0.165m)^2)(0.0095 T/s)
= - 0.0146 V
So the magnitude of the induced current is
I= e/R
=(0.0146 V)/( 4.66x 10^-4 ?)
= 31.34 A