Copper wire is wrapped around a cylindrical shell of height h=0.5 cm, forming a “toroid” coil...

Copper wire is wrapped around a cylindrical shell of height h=0.5 cm, forming a “toroid” coil whose inner radius is R1=10 cm and outer radius is R 2 13 cm ( as a result, the cross sectional area of the “toroid” is a rectangle and not a circle; the height of the rectangle is 0.5 cm and the width is 3 cm, as shown in the cross-section view below). The current in the coil is 2A and there are N=500 turns h aA) Apply Ampere’s law to find an expression for the magnetic field at a distance r from its center, where 10 cm<r<13 cmB) Find the magnetic flux through one of the turns of the toroidC) Find the total flux through the toroid and the inductance of the toroid.D) Find the magnetic energy and the magnetic energy densityE) Find the self-induced emf and the direction of self-induced current when the current I decreases, starting at 2 A, at a rate of 10 mA/s

Expert Solution

genius_generous answered 2 years ago

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