In: Physics
A 2.0 mm -diameter, 50 cm -long copper wire carries a 4.5 A current. What is the potential difference between the ends of the wire?
First find Resistance R =
l / (A)
A =
/4
(Diameter)2 Diameter =2.0 cm = 0.02 meters
= /4
( 0.02 )2
= 3.145
10-4 m2
Resistivity of copper
= 1.68
10-8 Ohm-meter
l = length of wire in meters
R =
l / (A) = 1.68
10-8
0.5 / ( 3.145
10-4)
= 2.671
10-5 Ohms
Potential difference between the end of the wire V = I R
= 4.2
2.671
10-5
V = 1.212
10-4 volts