In: Physics
A 2.0 mm -diameter, 50 cm -long copper wire carries a 4.5 A current. What is the potential difference between the ends of the wire?
First find Resistance R = l / (A)
A = /4 (Diameter)2 Diameter =2.0 cm = 0.02 meters
= /4 ( 0.02 )2
= 3.145 10-4 m2
Resistivity of copper = 1.68 10-8 Ohm-meter
l = length of wire in meters
R = l / (A) = 1.68 10-8 0.5 / ( 3.145 10-4)
= 2.671 10-5 Ohms
Potential difference between the end of the wire V = I R
= 4.2 2.671 10-5
V = 1.212 10-4 volts