In: Math
Use the magnitudes (Richter scale) of the earthquakes listed in the data set below. Find the mean and median of this data set. Is the magnitude of an earthquake measuring 7.0 on the Richter scale an outlier (data value that is very far away from the others) when considered in the context of the sample data given in this data set? Explain. Find the mean and median of the data set using a calculator or similar data analysis technology.
2.83 0.48 1.95 0.59 2.78 1.34 0.04 0.83 0.96 0.36
1.36 1.81 2.67 1.53 2.66 1.39 0.99 0.38 2.44 0.33
2.93 1.07 2.61 0.01 1.18 2.35 1.06 2.78 2.47 0.54
2.18 2.94 0.37 1.95 2.79 1.57 2.82 0.76 2.96 2.98
2.13 1.04 0.17 1.78 0.98 2.72 1.99 1.35 1.73 0.03
Is the magnitude of an earthquake measuring 7.0 on the Richter scale an outlier when considered in the context of the sample data given?
putting above data in ascending order:
s. no | x |
1 | 0.01 |
2 | 0.03 |
3 | 0.04 |
4 | 0.17 |
5 | 0.33 |
6 | 0.36 |
7 | 0.37 |
8 | 0.38 |
9 | 0.48 |
10 | 0.54 |
11 | 0.59 |
12 | 0.76 |
13 | 0.83 |
14 | 0.96 |
15 | 0.98 |
16 | 0.99 |
17 | 1.04 |
18 | 1.06 |
19 | 1.07 |
20 | 1.18 |
21 | 1.34 |
22 | 1.35 |
23 | 1.36 |
24 | 1.39 |
25 | 1.53 |
26 | 1.57 |
27 | 1.73 |
28 | 1.78 |
29 | 1.81 |
30 | 1.95 |
31 | 1.95 |
32 | 1.99 |
33 | 2.13 |
34 | 2.18 |
35 | 2.35 |
36 | 2.44 |
37 | 2.47 |
38 | 2.61 |
39 | 2.66 |
40 | 2.67 |
41 | 2.72 |
42 | 2.78 |
43 | 2.78 |
44 | 2.79 |
45 | 2.82 |
46 | 2.83 |
47 | 2.93 |
48 | 2.94 |
49 | 2.96 |
50 | 2.98 |
total | 79.96 |
average | 1.5992 |
mean =1.5992
median =middle value =(n+1)/2 th value =(1.53+1.57)/2 =1.55
Q1 =(n+1)/4 th value =(50+1)/4 th vale =0.8125
Q3 =(n+1)*3/4 th value =(50+1)*3/4 th vale =2.6225
hence outer fence =Q3+1.5*(Q3-Q1)=5.3375
as earthquake measuring 7.0 falls outside outer fence ; therefore it is an outlier.