Question

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Sample mean: x̄ = 48.74 Sample standard deviation: s = 32.5857 Size of your sample: n...

Sample mean: x̄ = 48.74

Sample standard deviation: s = 32.5857

Size of your sample: n = 50

What is your Point Estimate? (round each answer to at least 4 decimals)

For a 95% confidence interval

Solutions

Expert Solution

Solution :

Given that,

Point estimate = sample mean = = 48.74

sample standard deviation = s = 32.5857

sample size = n = 50

Degrees of freedom = df = n - 1 = 50 - 1 = 49

At 95% confidence level the t is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

t /2,df = t0.025,49 = 2.010

Margin of error = E = t/2,df * (s /n)

= 2.010 * (32.5857 / 50)

= 9.2627

The 95% confidence interval estimate of the population mean is,

- E < < + E

48.74 - 9.2627 < < 48.74 + 9.2627

39.4773 < < 58.0027

A 95% confidence interval: (39.4773 , 58.0027)


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