In: Math
Sample mean: x̄ = 48.74
Sample standard deviation: s = 32.5857
Size of your sample: n = 50
What is your Point Estimate? (round each answer to at least 4 decimals)
For a 95% confidence interval
Solution :
Given that,
Point estimate = sample mean = = 48.74
sample standard deviation = s = 32.5857
sample size = n = 50
Degrees of freedom = df = n - 1 = 50 - 1 = 49
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,49 = 2.010
Margin of error = E = t/2,df * (s /n)
= 2.010 * (32.5857 / 50)
= 9.2627
The 95% confidence interval estimate of the population mean is,
- E < < + E
48.74 - 9.2627 < < 48.74 + 9.2627
39.4773 < < 58.0027
A 95% confidence interval: (39.4773 , 58.0027)