Question

Sample mean: x̄ = 48.74

Sample standard deviation: s = 32.5857

Size of your sample: n = 50

1. What is your Point Estimate? (round each answer to at least 4 decimals)

For a 99% confidence interval:         Point estimate =

Answer 1

Given that,

= 48.74

s =32.5857

n = 50

point estimate=48.74

Degrees of freedom = df = n - 1 =50 - 1 = 49

At 99% confidence level the t is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

_{t /2  df} = t_0.005, 49=   2.680

Margin of error = E = t_/2,df * (s /n)

= 2.680* (32.5857 / 50) = 12.3503

The 99% confidence interval estimate of the population mean is,

- E < < + E

48.74- 12.3503< < 48.74+ 12.3503

36.3897< < 61.0903

( 36.3897,61.0903)