Calculate the percent ionization in a 0.1M solution of hydrofluoric acid (Ka=3.53*10^-4)

Expert Solution

HF <-------> H⁺ + F^-

Initial 0.1 0 0

Change - x +x +x

Equilibrium (0.1-x) x x

Ka = 3.53 * 10^-4 = x. x / (0.1-x)

x = 0.005767

Percent ionization = ( Ionized concentration / unionizedconcentration ) * 100

= ( 0.005767 / 0.1) * 100

=5.767 %

queen_honey_blossom answered 10 months ago

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