Question

In: Chemistry

(a) Calculate the percent ionization of 0.00690 M hypochlorous acid (Ka = 3e-08). % ionization =...

(a) Calculate the percent ionization of 0.00690 M hypochlorous acid (Ka = 3e-08). % ionization =

(b) Calculate the percent ionization of 0.00690 M hypochlorous acid in a solution containing 0.0300 M sodium hypochlorite. % ionization =

Expert Solution

a)

concentration of hypochlorous acid = C = 0.00690 M

[H+] = sqrt (Ka x C)

= sqrt (3 x 10^-8 x 0.00690)

= 1.438 x 10^-5 M

% ionization = ([H+] / C ) x 100

= (1.438 x 10^-5 / 0.00690 ) x 100

% ionization = 0.208 %

b)

ClO- + H2O ------------> HClO + OH-

0.03 0.00690 0

0.03 - x 0.00690 + x x

Kb = (x)(0.00690-x) / (0.03 - x)

3.33 x 10^-7 = 0.00690x - x^2 / 0.03 - x

x = 6.898 x 10^-3

[OH-] = 6.898 x 10^-3 M

% ionization = (6.898 x 10^-3 / 0.03 ) x 100

% ionization = 23.0 %

queen_honey_blossom answered 8 months ago

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