Question

In: Chemistry

why have I least change in( pH6.80) then (pH 7.70 )after the addition one-drop of HCl...

why have I least change in( pH6.80) then (pH 7.70 )after the addition one-drop of HCl or NaOH?

Solution

Measured pH

pH after addition of 1 drop 1 M HCl

pH after addition of 1 drop 1 M NaOH

pH after 10-fold

dilution

pH 6.80 Buffer

6.82

6.75

6.92

7.03

pH 7.70 Buffer

7.82

7.53

8.28

7.84

Solutions

Expert Solution

A buffer is any type of substance that will resist pH change when H+ or OH- is added.

This is typically achieved with equilibrium equations. Both type of buffer will resist both type of additions.

When a weak acid and its conjugate base are added, they will form a buffer

The equations:

The Weak acid equilibrium:

HA(aq) <-> H+(aq) + A-(aq)

Weak acid = HA(aq)

Conjugate base = A-(aq)

Neutralization of H+ ions:

A-(aq) + H+(aq) <-> HA(aq); in this case, HA is formed, H+ is neutralized as well as A-, the conjugate

Neutralization of OH- ions:

HA(aq) + OH-(aq) <-> H2O(l) + A-(aq) ; in this case; A- is formed, OH- is neutralized as well as HA.

Now,

For the weak base equilibrium:

B(aq) + H2O(l) <-> BH+(aq) + OH-(aq)

Weak base = B;

Conjugate acid = BH+

Neutralization of OH- ions:

BH+(aq) + OH-(aq) <-> B(aq) + H2O(l); in this case, OH- is neutralized by BH+, as well as B is created

Neutralization of H+ ions:

B(aq) + H+(aq) <-> BH+(aq)

Clearly, when adding H+, it get neutralized, and OH- as well..


Related Solutions

The pH of 0.1M NaCl is 7.14. After 1 drop of 0.1M HCl the pH change...
The pH of 0.1M NaCl is 7.14. After 1 drop of 0.1M HCl the pH change to 3.59. And after another 1 drop of 0.1M HCl the pH become 3.13. Why does pH change significantly 7.14 to 3.59? And also why the pH doesn't change very much after another 1 drop of 0.1M HCl (3.59 to 3.13)?
Initial pH: 2.54 malonic acid (C3H4O4) sodium malonate (NaC3H3O4) Addition of HCl (drop in pH) mL...
Initial pH: 2.54 malonic acid (C3H4O4) sodium malonate (NaC3H3O4) Addition of HCl (drop in pH) mL of HCl added ΔpH 4.12 -0.51 6.93 -0.69 11.59 -0.89 25.63 -1.09 49.9 -1.24 Addition of NaOH (increase in pH) mL of NaOH added ΔpH 1.91 2.77 2.61 3.00 3.56 3.21 4.43 3.48 4.98 3.69 5.39 3.96 5.87 4.25 6.36 4.51 6.9 4.71 Clearly outline how you made your assigned buffer with its target pH. Assuming no volume change, how many mL of 0.1...
I did a lab and it's asking for the theoretical pH with the addition of HCl....
I did a lab and it's asking for the theoretical pH with the addition of HCl. The procedure:measure out 5.0ml of 1.0ml acetic acid solution in a 100 ml graduated cylinder. dilute the 5.0 ml w/ water to a final volume 50.0 mL&stir.measure out 1.00ml of 1.0 M NaOH&add it to the acetic acid solution.stir the mixture.calculate the theoretical pH.
I did a lab and it's asking for the theoretical pH with the addition of HCl....
I did a lab and it's asking for the theoretical pH with the addition of HCl. The procedure:measure out 5.0ml of 1.0ml sodium acetate solution in a 100 ml graduated cylinder. dilute the 5.0 ml w/ water to a final volume 50.0 mL&stir.measure out 1.00ml of 1.0 M HCl&add it to the sodium acetate solution.stir the mixture.calculate the theoretical pH.
How does pH of 0.5L of pure water change upon addition of 0.5ml of 1M HCL?...
How does pH of 0.5L of pure water change upon addition of 0.5ml of 1M HCL? 0.5 ml of 1 M NaOH was added to 0.5L of a 100mM buffer solution at pH=7.0. Calculate how the pH value is affected by this addition if a pKa value of the buffer is 7.47.
calculate the initial pH and the pH after each 2ml addition of 0.10M NaOH. i) initial...
calculate the initial pH and the pH after each 2ml addition of 0.10M NaOH. i) initial pH a) 2ml of 0.10M of NaOH has added to 50ml of 0.50M HC2H3O2/0.050M NaC2H3O2 b) 8ml of 0.10M of NaOH has added to 50ml of 0.50M HC2H3O2/0.050M NaC2H3O2 c) 10ml of 0.10M of NaOH has added to 50ml of 0.50M HC2H3O2/0.050M NaC2H3O2
Which solution would show the least change in pH upon addition of 3.0 mL of 1.0...
Which solution would show the least change in pH upon addition of 3.0 mL of 1.0 M KOH? Assume equal volumes of each solution are used. Ka for CHO2H = 1.80 ✕ 10−4) a. A solution that is 0.50 M formic acid and 0.50 M sodium formate. b. A solution that is 0.10 M formic acid and 0.10 M sodium formate.    c. A solution that is 0.1 M formic acid d. A solution that is 0.50 M sodium formate
I) You have an HCl solution of pH 3.13. (a) The concentration of this solution is...
I) You have an HCl solution of pH 3.13. (a) The concentration of this solution is ______________ M (b) If you increased the HCl concentration exactly 2 fold, the pH would be ______________ (c) If you decrease the pH to 2.13, the new HCl concentration would be ______________ II) To 20.000 mL of distilled water in a 50 mL beaker, you add exactly 13 drops of 0.100 M HCl and swirl to mix. If exactly 18 drops of HCl are...
I need to take the code i already have and change it to have at least...
I need to take the code i already have and change it to have at least one function in it. it has to include one function and one loop. I already have the loop but cant figure out how to add a function. I thought i could create a funciton to call to the totalCost but not sure how to do it. Help please. #include #include //main function int main(void) {    char userName [20];    char yesOrNo [10];   ...
Calculate the pH of the solution after the addition of each of the given amounts of...
Calculate the pH of the solution after the addition of each of the given amounts of 0.0625 M HNO3 to a 80.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. 1) 0.00ml of HNO3 2) 8.03ml of HNO3 3) volume of HNO3 equal to half the equivalence point volume 4) 92.7ml of HNO3 5) volume of HNO3 equal to the equivalence point 6)100.98ml of HNO3
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT