In: Chemistry
why have I least change in( pH6.80) then (pH 7.70 )after the addition one-drop of HCl or NaOH?
Solution |
Measured pH |
pH after addition of 1 drop 1 M HCl |
pH after addition of 1 drop 1 M NaOH |
pH after 10-fold dilution |
pH 6.80 Buffer |
6.82 |
6.75 |
6.92 |
7.03 |
pH 7.70 Buffer |
7.82 |
7.53 |
8.28 |
7.84 |
A buffer is any type of substance that will resist pH change when H+ or OH- is added.
This is typically achieved with equilibrium equations. Both type of buffer will resist both type of additions.
When a weak acid and its conjugate base are added, they will form a buffer
The equations:
The Weak acid equilibrium:
HA(aq) <-> H+(aq) + A-(aq)
Weak acid = HA(aq)
Conjugate base = A-(aq)
Neutralization of H+ ions:
A-(aq) + H+(aq) <-> HA(aq); in this case, HA is formed, H+ is neutralized as well as A-, the conjugate
Neutralization of OH- ions:
HA(aq) + OH-(aq) <-> H2O(l) + A-(aq) ; in this case; A- is formed, OH- is neutralized as well as HA.
Now,
For the weak base equilibrium:
B(aq) + H2O(l) <-> BH+(aq) + OH-(aq)
Weak base = B;
Conjugate acid = BH+
Neutralization of OH- ions:
BH+(aq) + OH-(aq) <-> B(aq) + H2O(l); in this case, OH- is neutralized by BH+, as well as B is created
Neutralization of H+ ions:
B(aq) + H+(aq) <-> BH+(aq)
Clearly, when adding H+, it get neutralized, and OH- as well..