Calculate the pH of the solution at each step after the addition of i) 0.00mL ii)...

Calculate the pH of the solution at each step after the addition of i) 0.00mL ii) 2.30 mL, iii) 10.0 and iv) 16.0 mL of 0.50 M HCL to 100.0 mL of 0.10 M NH₃ solution.

Expert Solution

queen_honey_blossom answered 2 hours ago

Calculate the pH of the solution after the addition of each of the given amounts of...

Calculate the pH of the solution after the addition of each of the given amounts of 0.0625 M HNO3 to a 80.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. 1) 0.00ml of HNO3 2) 8.03ml of HNO3 3) volume of HNO3 equal to half the equivalence point volume 4) 92.7ml of HNO3 5) volume of HNO3 equal to the equivalence point 6)100.98ml of HNO3

Calculate the pH of each aqueous solution: I need step to step solution please using formula...

Calculate the pH of each aqueous solution: I need step to step solution please using formula from; pH = -log [H3O+] pOH = -log[OH-] pH + pOH = 14 1)0.80 M lactic acid and 0.40 M lactate ion. 2) 0.10 mol of formic acid, HCOOH, and 0.10 mol of sodium formate, HCOONa in 1 L of water . 3) 0.30 M NH3 and 1.50 M NH4+

calculate the initial pH and the pH after each 2ml addition of 0.10M NaOH. i) initial...

calculate the initial pH and the pH after each 2ml addition of 0.10M NaOH. i) initial pH a) 2ml of 0.10M of NaOH has added to 50ml of 0.50M HC2H3O2/0.050M NaC2H3O2 b) 8ml of 0.10M of NaOH has added to 50ml of 0.50M HC2H3O2/0.050M NaC2H3O2 c) 10ml of 0.10M of NaOH has added to 50ml of 0.50M HC2H3O2/0.050M NaC2H3O2

Calculate the pH of the solution after the addition of the following amounts of 0.0615 M...

Calculate the pH of the solution after the addition of the following amounts of 0.0615 M HNO3 to a 50.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. a) 0.00 mL of HNO3 b) 9.69 mL of HNO3 c) Volume of HNO3 equal to half the equivalence point volume d) 57.1 mL of HNO3 e) Volume of HNO3 equal to the equivalence point f) 65.3 mL of HNO3

a) Calculate the pH of 75 mL of the undiluted buffer solution after the addition of...

a) Calculate the pH of 75 mL of the undiluted buffer solution after the addition of 1 mL of 3 M HCl. b) Calculate the pH of 75 mL of the undiluted buffer solution after the addition of 15 mL of 3 M HCl. Buffer solution was made from 1 M of sodium acetate, and 1.1005 M of acetic acid. (pKa of acetic acid 4.75). pH of buffer = 4.79.

Calculate the pH of the solution after the addition of the following amounts of 0.0602 M...

Calculate the pH of the solution after the addition of the following amounts of 0.0602 M HNO3 to a 60.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. PLEASE ANSWER ALL PARTS: A, B, C, D, E, AND F. a) 0.00 mL of HNO3 b) 9.47 mL of HNO3 c) Volume of HNO3 equal to half the equivalence point volume d) 71.6 mL of HNO3 e) Volume of HNO3 equal to the equivalence point f) 78.6...

Calculate the pH of the solution after the addition of the following amounts of 0.0656 M...

Calculate the pH of the solution after the addition of the following amounts of 0.0656 M HNO3 to a 70.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. a) 0.00 mL of HNO3; Ph= b) 9.06 mL of HNO3; Ph= c) Volume of HNO3 equal to half the equivalence point volume; Ph= d) 77.0 mL of HNO3; Ph= e) Volume of HNO3 equal to the equivalence point; Ph= f) 83.8 mL of HNO3; Ph=

Calculate the pH of the solution after the addition of the following amounts of 0.0536 M...

Calculate the pH of the solution after the addition of the following amounts of 0.0536 M HNO3 to a 60.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. a) 0.00 mL of HNO3; Ph= b)8.28mL of HNO3; Ph= c) 42.0ml of HNO3 d) 84.0 mL of HNO3; Ph= f) 88.5 mL of HNO3; Ph=

Calculate the pH of the solution after the addition of the following amounts of 0.0649 M...

Calculate the pH of the solution after the addition of the following amounts of 0.0649 M HNO3 to a 70.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. a) 0.00 mL of HNO3 b) 7.30 mL of HNO3 c) Volume of HNO3 equal to half the quivalence point volume d) 77.5 mL of HNO3 e) Volume of HNO3 equal to the equivalence point f) 85.8 mL of HNO3 Please answer all parts of the question detailed...

Calculate the pH of the solution after the addition of the following amounts of 0.0568 M...

Calculate the pH of the solution after the addition of the following amounts of 0.0568 M HNO3 to a 80.0 mL solution of 0.0750 M aziridine. The pKa of aziridinium is 8.04. a) 0.00 mL of HNO3 b) 8.62 mL of HNO3 c) Volume of HNO3 equal to half the equivalence point volume d) 102 mL of HNO3 e) Volume of HNO3 equal to the equivalence point f) 89.2 mL of HNO3 thank you

Question