In: Math
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do twenty-year-olds have more cavities? The data show the results of a survey of 13 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal.
4, 7, 4, 6, 5, 4, 5, 5, 5, 5, 5, 4, 4
What can be concluded at the αα = 0.01 level of significance?
H0:H0: ? μ p ? = ≠ < >
H1:H1: ? p μ ? = ≠ < >
(a) t-test for a population mean
(b) Ho: μ ≤ 5 and H1: μ > 5
(c)
n = 13
μ = 5
s = 0.9
x-bar = 4.846
SE = s/√n = 0.9/√13 = 0.249615088
t = (x-bar - μ)/SE = (4.846 - 5)/0.249615088301353 = -0.617
(d) p-value = 0.7256
(e) p-value > α
(f) Fail to reject Ho
(g) The data suggest that the population mean number of cavities for twenty-year-olds is not significantly more than 5 at α = 0.01, so there is insufficient evidence to conclude that the population mean number of cavities for twenty-year-olds is more than 5
(h) If the population mean number of cavities for twenty-year-olds is 5 and if you survey another 13 twenty-year-olds then there would be a 72.5686636% chance that the sample mean for these 13 twenty-year-olds would be greater than 4.85
(i) If the population mean number of cavities for twenty-year-olds is 5 and if you survey another 13 twenty-year-olds, then there would be a 1% chance that we would end up falsely concluding that the population mean number of cavities for twenty-year-olds is more than 5.